Show that the Maxwell speed distribution function F(v) approaches zero by taking the limit as v → 0 and as v → ∞
Show that the Maxwell speed distribution function F(v) approaches zero by taking the limit as v → 0 and as v → ∞
The air molecules surrounding us aren't all traveling at an equivalent speed, albeit the air is all at one temperature. a number of the air molecules are going to be moving extremely fast, some are going to be moving with moderate speeds, and a few of the air molecules will hardly be moving in the least. A molecule during a gas could have anybody of an enormous number of possible speeds.
In the mid to late 1800s, James Clerk Maxwell and Boltzmann found out the solution to the present question. Their result's mentioned because the Maxwell-Boltzmann distribution, because it shows how the speeds of molecules are distributed for a perfect gas.
The average speed of a molecule within the gas is really located a touch to the proper of the height. the rationale the typical speed is found to the proper of the height is thanks to the longer tail on the proper side of the Maxwell-Boltzmann distribution graph.
Another useful quantity is understood because the root mean square speed. This quantity is interesting because the definition is hidden within the name itself. The basis mean square speed is that the root of the mean of the squares of the velocities. Mean is simply another word for average here.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
