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- See the image. a.Construct a context-free grammar generating C.Explain how your construction accounts for each rule. b.We could eliminate one rule from Cand make it regular. Which rule would that be, and why would it work? You do not need a formal proof, but you do need an explanation.Solve it!This is a question from my first Theory of Computing practice homework assignment included as an image. I need help with all three parts (a,b, and c) if possible.
- a. Write a BNF grammar for the language consisting of strings built only of the letters a and b. The strings may have any number of these letters, but the letter combinations bb must be in each string somewhere, and each string must start with a aa. For example, the strings aaabbabbba, aaaababba, and aababbabb are in the language, while a, bba, ababb, aabaa, and bbaa are not. b. Draw the parse tree for string aabbaaba according to the previous grammar: c. Describe, in complete English sentences and “layman’s terms,” the language defined by the following grammar in BNF (start symbol is <S> ): <S>::= <A>a|<B>b <C>::= c <A>::= a<A>a|<C> <B>::= b<B>b|<C>What can be claimed about the grammar G: {S→ alaRb, R→ b|bSa }? OA. G is a context-free grammar and L(G) is a context-free language. B. G is a context-free grammar but L(G) is actually a regular language. O C. G is a regular grammar and L(G) is a regular language. What can be said about the grammar G: {S → ORO|OR1|1RO|1R1, R → E|OR|1R }? OA. G is a context-free grammar and L(G) is a context-free language. B. G is a context-free grammar but L(G) is the regular language (0+1)²(0+1)* C. G is a regular grammar and L(G) is the regular language (0+1)(0+1)*Use the exhaustive search parsing method to parse the string abbbbbb with the grammar in Example 5.5. In general, how many rounds will be needed to parse any string w in this language?
- Answer the given question with a proper explanation and step-by-step solution.This question is about context-free grammars and parsing, and Turing machines (TM’s). Question 1) Consider the following context-free grammar G over the alphabet Σ = {a, b, c}: S → aSb | ε | acSba | abc Using any of the grammar transformation techniques we saw in this module, construct a CNFgrammar that generates the same language as the grammar G of Question 1.Make sure you include in your answer all individual steps that you followed. Please help me with this question :)need help with the question in the picture
- For this exercise, we will work on a regular grammar to recognize a comment in a C++ or Java program. A comment starts with /* and ends with */ and anything else in between can be ignored. We won't consider the case of nested comments. Keep in mind that you can have any number of * characters at the beginning, at the end, and in between. • Write a regular grammar recognizing such comments. • Draw the finite state machine for this grammar. • Draw a table for this grammar such as the ones for table-driver scanners in the class notes and in the book.For each of these languages, give both a context-free grammar and a push down automaton. Briefly explain how your CFG and PDA work. Your CFG should be relatively simple and contain at most 6 variables. For this question, your PDA cannot be directly convertedfrom your CFG (a)L1={ x#y | x is a prefix of yR, and y∈{a,b}* } ,Σ ={a,b,#} Recall that wR is w written backwards, and u is a prefix of v if v=ut for some stringt.For example bb#abb is in L1, but a#ab is not. (b)L2={ aibjck | i ≥ j or j ≥ k } (c)L3 = {w∈{a,b}* | w contains an unequal number of a’s and b’s}1. Use the algorithm described in class that takes a CFG and converts it into a CNF (Chomsky Normal Form) grammar that generates the same language as the original grammar, except possibly for the string A, to answer the following question. As part of your answer, you should say which variables are nullable, and you should give the appropriate grammar after each step of the algorithm. There are four steps. Give a CFG (context-free grammar) in CNF (Chomsky Normal Form) that generates the same language, except possibly for the string A, as the following grammar: SAB AB →bAa A → aaB bb