Show that the fields E and B are orthogonal.
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Show that the fields E and B are orthogonal. (Hint: remember the Faraday-Maxwell law)
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- Sailboats typically use metal vertically-oriented masts (the long support that holds up the sails.Given a 10m long mast and a boat speed of 4.0m/s, and earth’s surface B-field of roughly 1.0 gauss,how much voltage difference can we expect across the mast when sailing eastward? What part is mostpositive/negative on the mast?Calculate the value of an electric field at a point 5 m away from two positive electric charges of 69.9 µC and 20 μC that are located 10 m apart in vacuum. Provide your answer in Sl units. Answer: Choose...Consider an electron near the Earth's equator. In which direction does it tend to deflect if its velocity is (a) directed downward? (b) directed northward? (c) directed westward? (d) Directed southeastward? The answers are a) west b) zero deflection c) up d) down. Can you explain
- The direction of the electric field shown in each part is that produced by the charge distribution in the wire. Justify the direction shown in each part, using the Coulomb force law and the definition of E = F/q, where q is a positive test charge.1. Consider the four point charges arranged on the corners of a square as shown. Let the direction up towards the top of the page be N. The electric field at the center of the square will point (a) N (b) S (c) E (d) W (e) NE (d) NW (e) SE (f) SW +4 d 2. The diagram shows a current loop carrying current as shown. It is effectively (a) a north pole of a magnet (b) a south pole of a magnet (c) a monopole (d) not a magnet at allGive an example of a nonconstant field with zero divergence. Give an example of a field with a constant negative divergence.
- F=0.8975r^-2.00 And re-writing it as: (4)F=0.8975/r^-2.00 We can now compare it with Coulomb’s equation: (1)F=K|q1q2|/r^2 So, comparing these equations (4) and (1) we realize that: k=|q1q2|=0.8975 Plugging in values for charges: q1 = -10µC, and q2 = 10µC, isolating k (Coulomb’s constant), and recalling that 1µC = 10-6 C, we get: k|-10µC*10µC|=0.8975 k=0.8934/|-10µC*10µC|= 0.8934/10*10^-6C*10*10^-6C (3) Use this Example calculation above, and the trendline equation (3) coefficients that you have obtained on your graph, to find k. Show your work below. Be careful with powers of ten. k= 0.8975/|-10µC*10µC|= 0.8975/10*10^-6C*10*10^-6C = (5) Now, important part in reporting the answer is properly showing its units. To derive the SI units for Coulomb’s constant k, let’s look again at the equation (1), and re-write it as: k=F*r^2/|q1q2| (6) Recalling the units for all parameters in this equation: Force, F – Newtons, [N] Distance, r –…Is the acceleration always opposite to the direction of electric field lines