Show that the equation x - 17x +c = 0 has at most one solution in the interval [-2, 2]. Let f(x) = x - 17x + c for x in [-2, 2]. If f has two real solutions a and b in [-2, 2], with a < b, then --Select-- v. Since the polynomial f is continuous on [a, b] and differentiable on (a, b), --Select--- ) implies that there is a number r in (a, b) such that f'(r) = 0. Now f'(r) = . Since r is in (a, b), which is contained in [-2, 2], we have Irl < 2, so r² < 4. It follows that 3r2 - 17 ?v 3.4 – 17 = -5 ?v 0. This contradicts f'(r) = 0, so the given equation cannot have two real solutions in [-2, 2]. Hence, it has at most one real solution in [-2, 2].

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