The number of zeros of f(x) = 6x'– 7x +9x- 2 is , provided that each zero is counted according to its multiplicity.

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Polynomial Zeros and Multiplicity**

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**Concept: Counting Polynomial Zeros with Multiplicity**

The problem involves determining the number of zeros of a given polynomial function, considering the concept of multiplicity. The function in question is as follows:

\[ f(x) = 6x^7 - 7x^5 + 9x - 2 \]

**Question:**

The number of zeros of \( f(x) = 6x^7 - 7x^5 + 9x - 2 \) is \( \_\_\_\_ \), provided that each zero is counted according to its multiplicity.

**Explanation:**

When calculating the number of zeros of a polynomial function, it is essential to account for each zero's multiplicity. 

**Multiplicity** of a zero refers to the number of times that particular zero appears. For example, if \( x = 2 \) is a zero of the polynomial and it makes the polynomial \( g(x) \) become zero at \( x = 2 \) multiple times, the zero x = 2 may be captured as occurring more than once.

For a polynomial of degree \( n \), there are \( n \) zeros when counting multiplicity.

In the given polynomial function \( f(x) \):

- The highest power of \( x \) is \( x^7 \), thus the polynomial is of degree 7.
- Therefore, the number of zeros, counting multiplicity, is 7.

By answering as follows:

**Answer:**

The number of zeros of \( f(x) = 6x^7 - 7x^5 + 9x - 2 \) is **7**, provided that each zero is counted according to its multiplicity. 

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Transcribed Image Text:**Polynomial Zeros and Multiplicity** --- **Concept: Counting Polynomial Zeros with Multiplicity** The problem involves determining the number of zeros of a given polynomial function, considering the concept of multiplicity. The function in question is as follows: \[ f(x) = 6x^7 - 7x^5 + 9x - 2 \] **Question:** The number of zeros of \( f(x) = 6x^7 - 7x^5 + 9x - 2 \) is \( \_\_\_\_ \), provided that each zero is counted according to its multiplicity. **Explanation:** When calculating the number of zeros of a polynomial function, it is essential to account for each zero's multiplicity. **Multiplicity** of a zero refers to the number of times that particular zero appears. For example, if \( x = 2 \) is a zero of the polynomial and it makes the polynomial \( g(x) \) become zero at \( x = 2 \) multiple times, the zero x = 2 may be captured as occurring more than once. For a polynomial of degree \( n \), there are \( n \) zeros when counting multiplicity. In the given polynomial function \( f(x) \): - The highest power of \( x \) is \( x^7 \), thus the polynomial is of degree 7. - Therefore, the number of zeros, counting multiplicity, is 7. By answering as follows: **Answer:** The number of zeros of \( f(x) = 6x^7 - 7x^5 + 9x - 2 \) is **7**, provided that each zero is counted according to its multiplicity. ---
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