Show that In (x + √√x² + 1) = √√x² + 1² 1 & 1 . d_ \n(x + √ x² + 1) = x + √√x² + 1 dx d dx (

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
1
Show that In (x + √√x² + 1) = √2² + 1²
dx
1
d
d
& In (x + √√x² + 1) = x + √√x² + 1/ (
dx
dx
-√2/1
x + √x² + 1
1
x + √√√x² + 1
1
= x+√x² +1
1
x² + 1
1 +
2√√√√x² + 1
+1
x² + 1
+
√x² + 1
X
+1
Transcribed Image Text:1 Show that In (x + √√x² + 1) = √2² + 1² dx 1 d d & In (x + √√x² + 1) = x + √√x² + 1/ ( dx dx -√2/1 x + √x² + 1 1 x + √√√x² + 1 1 = x+√x² +1 1 x² + 1 1 + 2√√√√x² + 1 +1 x² + 1 + √x² + 1 X +1
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