Show that for any k > 3, any tree with a vertex of degreek must have at least k leaves. The proof that uses summations of the result that a tree always has two leaves is probably easiest to adapt here. You will want to assume ng > 1 in the summations

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1. Show that for any \( k \geq 3 \), any tree with a vertex of degree \( k \) must have at least \( k \) leaves. The proof that uses summations of the result that a tree always has two leaves is probably easiest to adapt here. You will want to assume \( n_k \geq 1 \) in the summations

\[
n = \sum_{j=1}^{\infty} n_j ; \quad \text{total degree} = \sum_{j=1}^{\infty} jn_j.
\]
Transcribed Image Text:1. Show that for any \( k \geq 3 \), any tree with a vertex of degree \( k \) must have at least \( k \) leaves. The proof that uses summations of the result that a tree always has two leaves is probably easiest to adapt here. You will want to assume \( n_k \geq 1 \) in the summations \[ n = \sum_{j=1}^{\infty} n_j ; \quad \text{total degree} = \sum_{j=1}^{\infty} jn_j. \]
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