Given a cube that has a side length of one, determine the greatest number of points that can be placed on the cube (located on faces or edges) so that for any 2 points they are at least one length apart from each other. To show that there is a x, number, you will have to draw x points that are all one length apart and provide mathematical proof that a collection of x+1 points has 2 points that are less then one apart. (This is a combinatorics and graph theory math problem)

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Given a cube that has a side length of one, determine the greatest number of points that can be placed on the cube (located on faces or edges) so that for any 2 points they are at least one length apart from each other. To show that there is a x, number, you will have to draw x points that are all one length apart and provide mathematical proof that a collection of x+1 points has 2 points that are less then one apart.

(This is a combinatorics and graph theory math problem)

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Step 1

It is given that a cube has side length of 1.

The objective is to determine the greatest number of points that can be placed on the cube so that any 2 points are at least one length apart from each other. 

The pigeonhole principle is used to prove the requirement.

The pigeonhole principle states that if n objects are placed in m holes with n>m, then at least one hole must contain more than one object.

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