Show that d given by d(x, y) = |x-ylis a metric on R by using definition 4.2.1. You may want to use the fact that x- z| = |x+y-y-zs |x-y\ + ly-z| to show part ii).
Show that d given by d(x, y) = |x-ylis a metric on R by using definition 4.2.1. You may want to use the fact that x- z| = |x+y-y-zs |x-y\ + ly-z| to show part ii).
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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
Transcribed Image Text:Definition 4.2.1. Suppose S is a non-empty set. A metric d is a function d:S x S [0, 0) such that
the following hold:
i). d(a, y) = 0 if and only if æ = y
ii). d(x, y) = d(y, æ) for all æ and y in S.
iii). d(x, z) < d(x, y) + d(y, z) for all a, y, z in S.
Show that d given by d(x, y) = x-y is a metric on IR by using definition 4.2.1. You may want to use the fact that x-z|= |x+y-y-zs
|x-y + ly-z| to show part ii).
Expert Solution

Step 1
we knew that given metric d(x,y) = |x-y| is always .
now d(x,y) = 0 |x-y| = 0
x-y = 0
x = y
hence (i) condition of 4.2.1 holds that d(x,y) = 0 if and only id x = y.
let x,y R be two arbitrary points.
then d(x,y) = |x-y| = |y-x| = d(y,x)
hence condition (ii) is satishfied that d(x,y) = d(y,x) , x,y R
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