Show that d given by d(x, y) = |x-ylis a metric on R by using definition 4.2.1. You may want to use the fact that x- z| = |x+y-y-zs |x-y\ + ly-z| to show part ii).

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Chapter2: Second-order Linear Odes
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Definition 4.2.1. Suppose S is a non-empty set. A metric d is a function d:S x S [0, 0) such that
the following hold:
i). d(a, y) = 0 if and only if æ = y
ii). d(x, y) = d(y, æ) for all æ and y in S.
iii). d(x, z) < d(x, y) + d(y, z) for all a, y, z in S.
Show that d given by d(x, y) = x-y is a metric on IR by using definition 4.2.1. You may want to use the fact that x-z|= |x+y-y-zs
|x-y + ly-z| to show part ii).
Transcribed Image Text:Definition 4.2.1. Suppose S is a non-empty set. A metric d is a function d:S x S [0, 0) such that the following hold: i). d(a, y) = 0 if and only if æ = y ii). d(x, y) = d(y, æ) for all æ and y in S. iii). d(x, z) < d(x, y) + d(y, z) for all a, y, z in S. Show that d given by d(x, y) = x-y is a metric on IR by using definition 4.2.1. You may want to use the fact that x-z|= |x+y-y-zs |x-y + ly-z| to show part ii).
Expert Solution
Step 1

we knew  that given metric d(x,y) = |x-y| is always 0.

 now d(x,y) = 0  |x-y| = 0

                         x-y = 0

                          x = y

hence (i) condition of 4.2.1 holds that d(x,y) = 0 if and only id x = y.

let x,y  R be two arbitrary points.

 then d(x,y) = |x-y| = |y-x| = d(y,x)

hence condition (ii) is satishfied  that  d(x,y) = d(y,x) , x,y  R

 

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