Show me the balances for each subsequent system: overall, air conditioner, mixing point, and splitting point. Material balances
Show me the balances for each subsequent system: overall, air conditioner, mixing point, and splitting point. Material balances
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Show me the balances for each subsequent system: overall, air conditioner, mixing point, and splitting point. Material balances
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Example 4.5-1
Equipment Encyclopedia
reactor, condenser
www.wiley.com/college/felder
Solution
143 of 695
Material and Energy Balances on an Air Conditioner
Q Search
Fresh air containing 4.00 mole% water vapor is to be cooled and dehumidified to a water content of
1.70 mole % H₂O. A stream of fresh air is combined with a recycle stream of previously dehumidified air
and passed through the cooler. The blended stream entering the unit contains 2.30 mole% H₂O. In the air
conditioner, some of the water in the feed stream is condensed and removed as liquid. A fraction of the
dehumidified air leaving the cooler is recycled and the remainder is delivered to a room. Taking 100 mol
of dehumidified air delivered to the room as a basis of calculation, calculate the moles of fresh feed,
moles of water condensed, and moles of dehumidified air recycled (a) manually, and (b) using Excel's
Solver.
The labeled flowchart for this process, including the assumed basis of calculation, is shown below. Dashed
lines depict the four subsystems about which balances might be written the overall process, the recycle-
fresh feed mixing point, the air conditioner, and the recycle-product gas splitting point. The quantities to be
determined are n₁, n3, and n5.
n₁ (mol)
0.960 DA
0.040 W (v)
n₂(mol)
DA = dry air
W water
n
0.977 DA
0.023 W(v)
ng(mol)
0.983 DA
0.017 W(v)
AIR
COND.
n3[mol W(1)]
n4(mol)
{}
0.983 DA
0.017 W(v)
8
100 mol
0.983 DA
0.017 W(v)
(a) Manual solution. Students first attempting recycle problems are tempted to jump in and start
writing balances immediately, and when they do they find themselves spending a long time on the
problems, often failing to get solutions. If you first take a few minutes to go through a degree-of-
freedom analysis you should be able to work out an efficient solution method before doing
any calculations, ultimately saving yourself much more time than it took to do the analysis.
Observe the procedure.
{"
8
33
ENG
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PDF Elementary Principles of Chemica X PDF *Elementary Principles of Chemic X +
83°F
Mostly cloudy
Ⓒ File | E:/Elementary%20Principles%20of%20Chemical%20Processes,%204th%20Edition%20(%20PDFDrive%20).pdf
Draw
(T) Read aloud
Example 4.5-1
Equipment Encyclopedia
reactor, condenser
www.wiley.com/college/felder
Solution
143 of 695
Material and Energy Balances on an Air Conditioner
Q Search
Fresh air containing 4.00 mole% water vapor is to be cooled and dehumidified to a water content of
1.70 mole % H₂O. A stream of fresh air is combined with a recycle stream of previously dehumidified air
and passed through the cooler. The blended stream entering the unit contains 2.30 mole% H₂O. In the air
conditioner, some of the water in the feed stream is condensed and removed as liquid. A fraction of the
dehumidified air leaving the cooler is recycled and the remainder is delivered to a room. Taking 100 mol
of dehumidified air delivered to the room as a basis of calculation, calculate the moles of fresh feed,
moles of water condensed, and moles of dehumidified air recycled (a) manually, and (b) using Excel's
Solver.
The labeled flowchart for this process, including the assumed basis of calculation, is shown below. Dashed
lines depict the four subsystems about which balances might be written the overall process, the recycle-
fresh feed mixing point, the air conditioner, and the recycle-product gas splitting point. The quantities to be
determined are n₁, n3, and n5.
n₁ (mol)
0.960 DA
0.040 W (v)
n₂(mol)
DA = dry air
W water
n
0.977 DA
0.023 W(v)
ng(mol)
0.983 DA
0.017 W(v)
AIR
COND.
n3[mol W(1)]
n4(mol)
{}
0.983 DA
0.017 W(v)
8
100 mol
0.983 DA
0.017 W(v)
(a) Manual solution. Students first attempting recycle problems are tempted to jump in and start
writing balances immediately, and when they do they find themselves spending a long time on the
problems, often failing to get solutions. If you first take a few minutes to go through a degree-of-
freedom analysis you should be able to work out an efficient solution method before doing
any calculations, ultimately saving yourself much more time than it took to do the analysis.
Observe the procedure.
{"
8
33
ENG
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00
:
7:36 PM
7/5/2023
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