Data is the first picture, questions on the second paper Run12Data sheet - Part A:1. Show your calculations for moles of I, reacted: (find through moles of $₂03²)Molarity x Volume= 0,01 0.0025L = 2.5.10 5 1/232. Show your calculation for molarity of 1₂ reacted [AI₂]: (divide moles reacted by total reaction volume)Total volume of solution = 2,5 ml + 5 ml + 15ml + 5ml = 27,5 MLMolanty of 12 react = 1.25*10'5 x 1000/27.5 mL-14,55 x 10" MTemp (°C)12222.0621.8°C1.25×10 ³ moles21.5°CInitial [I-](M)ODIS0.0180.009Initial [H₂O2](M)0.0180.0090.018Reaction Time (in s)AtSet +1:53mins #103 s341mins 208 second2:18mins S131sReaction Rate (in Ms¹)= [ΔΙ] / Δt0.00017 4760.000086540.0000687 Show calculations for x and y: (Include appropriate units, attach a separate sheet if necessary)x = _____________y=___________Show calculations for k:k (run 1) =(round to the nearest whole number)k (run 2) =Rate Law:k (run 3) =Average k=

Rate = k [I-]x [H2O2]y k: Rate Constant x,y: OrderRate 1/2 = k [0.018]x[0.018]y / k [0.018]x[0.009]y (0.00017476/0.00008654) = (0.018/0.009)y 2.019 = 2y y = 1 Similarly, Rate 2/3 = (0.018/0.009)x (0.00008654/0.0000687) = 2x 1.25 = 2x x = 0Now, Rate = k [I-]0[H2O2] So, Rate 1 = k * 0.018 M k (1) = 0.00017476 / 0.018 s-1 = 0.0097 s-1 Similarly- k(2) = 0.00008654 / 0.009 = 0.0096 s-1 k (3) = 0.0000687 / 0.018 = 0.0038 s-1 Average k = (0.0097+0.0096+0.0038)/3 = 0.0077 s-1