Show all your calculation work to solve the following mass-mass stochiometry problem; How many grams of zinc (II) chloride (ZnCl2) are produced if 6.5 grams of zinc (Zn) are used in a chemical reaction according to the following equation. Zn(s) + 2HCl(aq) --> ZnCl (aq) + H2 (g) What is the given and desired chemical? Molar masses: Zn= 65.38 g/mol. H2= 2.016 g/mol ZnCl2=136.29 g/mol HCl=36.5 g/mol Solve EXACTLY like the exmaple attached. Apply the significant figure rules to your final answer.
Show all your calculation work to solve the following mass-mass stochiometry problem; How many grams of zinc (II) chloride (ZnCl2) are produced if 6.5 grams of zinc (Zn) are used in a chemical reaction according to the following equation. Zn(s) + 2HCl(aq) --> ZnCl (aq) + H2 (g) What is the given and desired chemical? Molar masses: Zn= 65.38 g/mol. H2= 2.016 g/mol ZnCl2=136.29 g/mol HCl=36.5 g/mol Solve EXACTLY like the exmaple attached. Apply the significant figure rules to your final answer.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
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- Show all your calculation work to solve the following mass-mass
stochiometry problem;
How many grams of zinc (II) chloride (ZnCl2) are produced if 6.5 grams of zinc (Zn) are used in a
Zn(s) + 2HCl(aq) --> ZnCl (aq) + H2 (g)
What is the given and desired chemical?
Molar masses:
Zn= 65.38 g/mol. H2= 2.016 g/mol
ZnCl2=136.29 g/mol HCl=36.5 g/mol
Solve EXACTLY like the exmaple attached. Apply the significant figure rules to your final answer.
![Problem #1
How many grams of silver chloride (AgCl) are produced from 5.0 g of
silver nitrate (AgNO) reacting with an excess of barium chloride??
Ba(NO3)2 (s) + 2AgCl (s)
moles
mass
2AgNO3 (s) +
5.0 g
Molar masses of all compounds in the equation:
AgNO3: 169.88 g/mol
Ba(NO3)2:
BaCl₂: 208.23 g/mol
AgCl:
5.0 g AgNO3
BX C1₂ (5)
Setup & solve the problem, below:
"excess"
more than
enough
1 mol AgNO3
2 mol AgCl
169.88 g AgNO3 2 mol AgNO3
وه و ..
261.35 g/mol
143.32 g/mol
143.32 g AgCl
1 mol AgCl
=
4.2 g
339.76
4.21827
4.2 g AgCl
volume
Avogodno's a
mole satin
MOLL
Avogodro's a
INSTAL
partičku
Melum
Convert mass (grams) of the given chemical to moles of the
given chemical using its molar mass.
Which chemical is "desired"?
AgCl
Convert moles of the given chemical to moles of the desired
chemical using mole ratio.
3. Convert moles of the desired chemical to mass (grams) of
the desired chemical using its molar mass.
Answer these questions before you begin:
Which chemical is "given"?
AgNO3
(2)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F13d63635-0b69-41e9-98ce-4d5f3ff4bff4%2F054a6cc1-bbdd-4bab-ab7b-2c9f9735aed4%2Foqlcj4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Problem #1
How many grams of silver chloride (AgCl) are produced from 5.0 g of
silver nitrate (AgNO) reacting with an excess of barium chloride??
Ba(NO3)2 (s) + 2AgCl (s)
moles
mass
2AgNO3 (s) +
5.0 g
Molar masses of all compounds in the equation:
AgNO3: 169.88 g/mol
Ba(NO3)2:
BaCl₂: 208.23 g/mol
AgCl:
5.0 g AgNO3
BX C1₂ (5)
Setup & solve the problem, below:
"excess"
more than
enough
1 mol AgNO3
2 mol AgCl
169.88 g AgNO3 2 mol AgNO3
وه و ..
261.35 g/mol
143.32 g/mol
143.32 g AgCl
1 mol AgCl
=
4.2 g
339.76
4.21827
4.2 g AgCl
volume
Avogodno's a
mole satin
MOLL
Avogodro's a
INSTAL
partičku
Melum
Convert mass (grams) of the given chemical to moles of the
given chemical using its molar mass.
Which chemical is "desired"?
AgCl
Convert moles of the given chemical to moles of the desired
chemical using mole ratio.
3. Convert moles of the desired chemical to mass (grams) of
the desired chemical using its molar mass.
Answer these questions before you begin:
Which chemical is "given"?
AgNO3
(2)
![Significant Figure Rules
All nonzero digits are significant.
Zeros that appear between other
nonzero digits are always significant.
Zeros that appear in front of all of the
nonzero digits are called left-end zeros.
Left-end zeros are never significant.
Zeros that appear after all nonzero
digits are called right-end zeros.
Right-end zeros in a number that lacks
a decimal point are not significant.
Right-end zeros in a number with a
decimal point are significant.
This is true whether the zeros occur
before or after the decimal point.
1
237 has three significant figures.
1.897 has four significant figures.
39,004 has five significant figures.
5.02 has three significant figures.
0.008 has one significant figure.
0.000416 has three significant figures.
140 has two significant figures.
75,210 has four significant figures.
620.0 has four significant figures.
19.000 has five significant figures.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F13d63635-0b69-41e9-98ce-4d5f3ff4bff4%2F054a6cc1-bbdd-4bab-ab7b-2c9f9735aed4%2Fd2pnuw_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Significant Figure Rules
All nonzero digits are significant.
Zeros that appear between other
nonzero digits are always significant.
Zeros that appear in front of all of the
nonzero digits are called left-end zeros.
Left-end zeros are never significant.
Zeros that appear after all nonzero
digits are called right-end zeros.
Right-end zeros in a number that lacks
a decimal point are not significant.
Right-end zeros in a number with a
decimal point are significant.
This is true whether the zeros occur
before or after the decimal point.
1
237 has three significant figures.
1.897 has four significant figures.
39,004 has five significant figures.
5.02 has three significant figures.
0.008 has one significant figure.
0.000416 has three significant figures.
140 has two significant figures.
75,210 has four significant figures.
620.0 has four significant figures.
19.000 has five significant figures.
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