Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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![**Topic: Verifying Equivalent Equations in Electrical Circuits**
**Objective:**
Show ALL steps to verify the following equations are equivalent.
\[ E = Ir + IR \]
and
\[ I = \frac{E}{r+R} \]
**Steps to Verify the Equations:**
1. **Starting with the given equations:**
- Equation 1: \( E = Ir + IR \)
- Equation 2: \( I = \frac{E}{r+R} \)
2. **Manipulate Equation 1 to express \( I \):**
\[ E = I (r + R) \]
3. **Isolate \( I \) on one side of the equation:**
\[ I = \frac{E}{r + R} \]
4. **Compare the manipulated Equation 1 with Equation 2:**
- They are identical in form:
\[ I = \frac{E}{r+R} \]
This shows that both equations are equivalent.
### Explanation:
- **Equation 1** represents Ohm's Law as applied to a circuit with internal resistance \( r \) and external resistance \( R \).
- **Equation 2** is a reformulation of the same relationship, isolating the current \( I \) and showing it as a function of the total resistance \( r + R \).
By manipulating the first equation and deriving the second equation, we have demonstrated the equivalence of these two electrical principles, often used in analyzing simple circuits.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4fcdecb9-56df-4c9c-aece-60df7fbe5b7a%2F9fcf4e14-722d-4961-9032-ebf88ae8f717%2Fpopna8_processed.png&w=3840&q=75)
Transcribed Image Text:**Topic: Verifying Equivalent Equations in Electrical Circuits**
**Objective:**
Show ALL steps to verify the following equations are equivalent.
\[ E = Ir + IR \]
and
\[ I = \frac{E}{r+R} \]
**Steps to Verify the Equations:**
1. **Starting with the given equations:**
- Equation 1: \( E = Ir + IR \)
- Equation 2: \( I = \frac{E}{r+R} \)
2. **Manipulate Equation 1 to express \( I \):**
\[ E = I (r + R) \]
3. **Isolate \( I \) on one side of the equation:**
\[ I = \frac{E}{r + R} \]
4. **Compare the manipulated Equation 1 with Equation 2:**
- They are identical in form:
\[ I = \frac{E}{r+R} \]
This shows that both equations are equivalent.
### Explanation:
- **Equation 1** represents Ohm's Law as applied to a circuit with internal resistance \( r \) and external resistance \( R \).
- **Equation 2** is a reformulation of the same relationship, isolating the current \( I \) and showing it as a function of the total resistance \( r + R \).
By manipulating the first equation and deriving the second equation, we have demonstrated the equivalence of these two electrical principles, often used in analyzing simple circuits.
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