- shorteningQuestion 4The inverted T beam shown in Figure Q4 carries a uniformly distributed load of 40 kN/m and a concentratedload of 75 kN.(a) Draw the bending moment diagram for the beam indicating the values at all principal sections.[13 marks](b) Calculate the second moment of area of the cross-section with respect to the horizontal neutral axis.[4 marks](c) Calculate the maximum normal stress in tension and compression due to bending.(d) Sketch the normal stress distribution over the cross-section, at the location of maximum bendingmoment, stating all important values.[4 marks][4 marks]228A40 kN/mIse1.5 mBCentroid of area of cross-section3 m75 kN- 60C2 m600V160-400Cross-section (dimensions in mm)Figure Q4tens-veCamp

(a) Drawing the bending moment diagram:The bending moment diagram shows how the bending moment…

Answered: - shortening Question 4 The inverted T…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Shear stress( NEED NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE).
A thin beam with a solid rectangular cross-section is loaded as shown in Figure Q7 below. L/3 L/3 L/3 Figure Q7 Consider the following statoments and select which combination correctly describes the bending moment diagram for this beam, along its longth using the sign conventions provided in lectures. i lt is symmetrical. ii It has a value of zero at the mid-point. i. It has a negative value for the entire length of the beam. iv. It is described by a quadratic (2nd order) function. O ali and i. are both correct. Ob.li. and iv. are both correct. Oci. and i. are both correct. Od.i. and iv. are both correct. Oe. li. and iv. are both correct. O. None of the provided answers are correct. OBi and i. are both correct.
Figure 1 shows a 4 m length of a simply supported beam with a pinned support at A and roller support at C. The beam carries a concentrated load of 16 kN at B. Show the Free Body Diagram (FBD) of the beam then determine the reaction force. a. Calculate the shear force, V. Draw Shear Force Diagram (SFD). C. Calculate the bending moment, M. Draw the Bending Moment Diagram (BMD). b. 16 kN A -1 m→ - 3 m- Figure 1
An extruded polymer beam is subjected to a bending moment M. The length of the beam is L = 500 mm. The cross-sectional dimensions of the beam are b1 = 35 mm, d1 = 115 mm, b2 = 21 mm, d2 = 21 mm, and a = 7 mm. For this material, the allowable tensile bending stress is 15 MPa, and the allowable compressive bending stress is 14 MPa. Determine the largest moment M that can be applied as shown to the beam. b2 a M d2 d1 A B L b1 Answer: M = i N-m
1. The cantilever beam in Figure 1 is fixed at A, and is loaded with a distributed load from A to B and a concentrated moment at C. Use the GRAPHICAL METHOD to plot the shear force and bending moment diagrams for the entire length of the beam. Label values at all key locations on the plots (at changes in loads, maxima, minima, and zeroes). Annotate your diagrams to explain how they were drawn (e.g. "AQAB = (-12 kN/m)(1 m) = -12 kN" and "(dQ/dx)AB = -12 kN/m"). 12 kN/m 5 kNm ZA B D 1 m 0.5 m 0.5 m Figure 1.
A simply supported beam carrying floor joist shown in Figure 6.22 is made of rectangular wood having a dimension of 50mm x 100mm. Compute the bending stress in tension and compression.
Please write the complete solutions and Legibly. Thumbs up will given! A W 310 X 52 steel beam is subjected to a point load P = 56 kN and a transverse load V = 15kN at B. The beam has length L = 2 m. See the table for beam properties. (Assume that the structure behaves linearly elastically and that the stresses caused by two or more loads may be superimposed to obtain the resultant stresses acting at a point. Consider both in-plane and out-of-plane shear stresses unless otherwise specified. (Do not use rounded intermediate values in your calculations) (a) Calculate the principal normal stresses and the maximum shear stress on element D located on the web right below the top flange and near the fixed support. Neglect the weight of the beam. (Enter your answers in MPa. For the normal stresses, use the deformation sign convention. For the shear stress, enter the magnitude.) σ1 = MPa σ2 = MPa τmax = MPa (b)…
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The beam is subjected to a point load and a distribution load as shown in Figure 2-1 below, and the right end is a build-in support. (1ft=12inch, ksi=kilo lb/in2)(a) Find the reaction in build-in support C.(b) Draw a Shear Force Diagram in the beam BC interval.(c) Draw a Moment Diagram in the beam BC interval.(d) Find the maximum shear stress mmax in the beam BC interval.(e) Find the maximum tensile flexural stress mmax, T and maximum compressive flexural stress mmax, C in the beam BC interval, respectively.
Part 1 For the simply supported beam subjected to the loading shown, derive equations for the shear force Vand the bending moment M for any location in the beam. (Place the origin at point A.) Let a-10.5 ft, b-24.0 ft, P- 20 kips and w - 5.5 kips/ft. Construct the shear-force and bending-moment diagrams on paper and use the results to answer the questions in the subsequent parts of this GO exercise. B Calculate the reaction forces Ay and Cy acting on the beam. Positive values for the reactions are indicated by the directions of the red arrows shown on the free-body diagram below. (Note: Since A, - 0, it has been omitted from the free-body diagram.) Answers: kips Cy- kips Part 2 Determine the shear force acting at each of the following locations: (a) x = 10.5-ft (i.e., just to the left of point B) (b) x = 10.5+ ft (i.e., just to the right of point B) (c) x = 32.5 ft Note that x-0 at support A. When entering your answers, use the shear-force sign convention detailed in Section 7.2.…
A built-in cantilever beam with a hollow rectangular cross-section is subjected to a uniformly distributed load as shown in Figure Q1 below. Which of the following statements best describes the shear force variation along the length, in the x direction, using the sign conventions provided in lectures? Figure Q1 O a ltis constant and positive throughout the length. Ob.it is constant and negative throughout the length. Ocit begins as a negative value and increases linearly to reach a positive value of the same magnitude. Od. None of the provided answers are correct. Oelt begins with a positive constant value for half the length, then suddenly decreases to a negative value, remaining constant for the remaining length. Of. It increases linearly from zero, then continues at a constant value before decreasing linearly to reach a value of zero again. Og It begins as a positive value and decreases linearly to reach a value of zero at the end of the length of the beam.

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