Short Problem: Given a parallel RLC circuit comprised of the following element: 61.64-ohm resistor, ideal inductor with reactance of 40.43 ohms; and a capacitor with reactance of 16.43 ohms. Compute for reactive power in VArs given an ac voltage source of 100 cis 0 volts. Give only the absolute value. Note: Follow this reminder carefully. Compute to the nearest 4 decimal places. No Scientific notation. Do not round off in the middle of calculation. Use stored values. Write the numerical values only. No units in your final answer. Spaces are not allowed. Excessive number of decimals as compared to the required number of decimals may result to an incorrect answer.

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Short Problem: Given a parallel RLC circuit comprised of the following element: 61.64-ohm resistor, ideal inductor with reactance of 40.43 ohms;
and a capacitor with reactance of 16.43 ohms. Compute for reactive power in VArs given an ac voltage source of 100 cis 0 volts. Give only the
absolute value.
Note: Follow this reminder carefully. Compute to the nearest 4 decimal places. No Scientific notation. Do not round off in the middle of calculation.
Use stored values. Write the numerical values only. No units in your final answer. Spaces are not allowed. Excessive number of decimals as
compared to the required number of decimals may result to an incorrect answer.
Transcribed Image Text:Short Problem: Given a parallel RLC circuit comprised of the following element: 61.64-ohm resistor, ideal inductor with reactance of 40.43 ohms; and a capacitor with reactance of 16.43 ohms. Compute for reactive power in VArs given an ac voltage source of 100 cis 0 volts. Give only the absolute value. Note: Follow this reminder carefully. Compute to the nearest 4 decimal places. No Scientific notation. Do not round off in the middle of calculation. Use stored values. Write the numerical values only. No units in your final answer. Spaces are not allowed. Excessive number of decimals as compared to the required number of decimals may result to an incorrect answer.
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