Shell. Consider a cylindrical shell with inner radius a and outer radius b carrying a total current I. The current density is given by J(r) = = 31 ·r 2π (b³ — a³)' - h ← a
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What is the magnitude of the magnetic field in the space enclosed by the shell (r<a)?
What is the magnitude of the magnetic field inside the shell (a<r<b)?
What is the magnitude of the magnetic field outside the shell?
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- 1 %AV |11. V;IV then total charge which crosses the section in time dt is dq = nAevdt. Since current is the rate of flow of charge, it is given as dg nAevdt = nAev dt dt Current density, J == nev ampere/metre Assuming a normal current density J= 1.55 x 10° A/m?, n = 10° for a copper conductor and e =1.6 x 10-19 coulomb, we get 1.55 x 10 = 1029 x 1.6 x 10-19 × v v = 9.7 x 10-5 m/s Example 3: The charge flowing through the imaginary surface in Fig. 7 is 0.16 C every 64 ms. Detemine the current in amperes. Example 4: Determine the time required for 4 x 101 electrons to pass through the imaginary surface in Fig. 7 if the current is 5 mA Example 5: A conductor material has a free-electron density of 1024 electrons per metre', when a voltage is applied, a constant drift velocity of 1.5x10° meter/second is attained by the electrons. If the cross-sectional area of the material is 1 cm?, calculate the magnitude of the current. (Answer: I=0.24 A) Example 6: A copper wire of are 5mm2 has a…HelpThe magnitude J of the current density in a certain wire with a circular cross section of radius R = 2.00 mm is given by J = (3.34 × 108),², with Jin amperes per square meter and radial distance r in meters. What is the current through the outer section bounded by r = 0.926R and r = R? Number i 2.392 Units mA
- Two copper wires A and B have the same length and are connected across the same battery. If R, = 5R A, determine the following. %D `A' HINT (a) the ratio of their cross-sectional areas Ав %3D AA (b) the ratio of their resistivities PB РА (c) the ratio of the currents in each wire IB 'AA wire has a radius of 2.5 m. The current density carried by the wire is a function of distance from the center of the wire is given by J(r) = C exp(-r2/L2) (A/m2), where C = 7.6 A/m2, and L = 2.7 m. Calculate the total amount of current carried by the wire, in A. (Please answer to the fourth decimal place - i.e 14.3225)A metal wire of cross-sectional area 2.00x10-6 m² and length 4.0 m has a current of 25.0 A uniformly distributed across that area. If the conductivity of the metal is, 5.9x107 (.m)-!, calculate the magnitude of the electric field, in V/m, along the wire?
- Can you solve this question pleaseIf a wire of radius a = 9.0 mm has got non-uniform current density J = Jo (1- (r/ a)) where r is radial distance, what's the resulting current? (Jo = 4.8 x 10“ A/m²) (Pi=3.14 , Your result should be in A, Your answer must include 2 digit after the decimal point. Maximum of %1 of %3D error accepted in your answer.) 452.164 cm2the amount of charge inside a cylindrical wire of length L with resistivity ρ of cross-sectionIt changes depending on time as q (t) = 3t2 - 2t + 4 (C). a) Calculate the amount of current flowing through the cross section of the wire at time t = 2 s. b) Find the current density J at time t = 3 s.
- A wire of resistivity 2.8 x 10^-8 ohm. m and length 20-m must dissipate electrical energy at a rate less than 3.0-W when a 15-A current flows. Calculate the minimum cross-sectional area of the wire.a) If the electron concentration increase along the x-axis of a conductor as shown in equation below: n= 3. 10"x + 2. 10"x + 1020 And D = 1.2 x 10-m/s. Find the diffusion current at x = 5mm?Find the current | through a resistor of resistance R = 2 Q if the voltage across the resistor is 6 V.