Shamma computed a z-based confidence interval for the mean weight of ZU female students as (69.54, 73.46). Which of the following could be a t- based interval using the same data? O (69.789, 73.211) O (69.436, 73.564) O (69.54, 73.46) O (69.855, 73.145)
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- A statistician chooses 27 randomly selected dates, and when examining the occupancy records of a particular motel for those dates, finds a standard deviation of 5.86 rooms rented. If the mumber of rooms rented is normally distributed, find the 95% confidence interval for the population standard deviation of the number of rooms rented. A)(4.615, 64.492) B) (4.615, 8.031) C)(21.297, 28.031) D)(21.297, 64.492)A sample of 36 breastfed infants found that 2 of them developed iron deficiency by age 5.5 months. Using the plus-four method, what is the 95% confidence interval for the population proportion of breastfed infants who have iron deficiency? Choose from available choices. a. (-0.0193, 0.1304) b. (-0.0072, 0.1184) c. (0.0071, 0.1929)From 2014 to 2017, annual terrorism-related deaths in Afghanistan were, in order, 5414, 6216, 6142, 6092 persons. What is an 90% confidence interval for the average number of deaths to the nearest whole number? a. 5529 to 6403 b. 5092 to 6840 c. None of the other answers are correct d. 5355 to 6577
- A student was asked to find a 90% confidence interval for widget width using data from a random sample of size n = 20. Which of the following is a correct interpretation of the interval (11.5,21.6)? There is a 90% chance that the mean of a sample of 20 widgets will be between 11.5 and 21.6. The mean width of all widgets is between 11.5 and 21.6, 90% of the time. We know this is true because the mean of our sample is between 11.5 and 21.6. With 90% confidence, the mean width of a randomly selected widget will be between 11.5 and 21.6. We are 90% confident the mean width of all widgets is between 11.5 and 21.6. There is a 90% chance that the mean of the population is between 11.5 and 21.6.During the nutrition research, the amount of consumed kilocalories per day was measured for 18 people - 10 women and 8 men. Results are as follows: Women: 1624, 1608, 2003, 1654, 1907, 1636, 1924, 1868, 1578, 2010; Men: 2360, 2547, 2524, 2056, 2172, 2464, 2253, 1954. Calculate a 95% confidence interval on the mean for women and men separately. Assume distribution to be normal. Round your answers to the nearest integer (e.g. 9876). Women: i i Men: iA researcher investigated whether the temperature of milk, x, can be used to predict the milk's pH content, y. She predicted the pH level of a glass of milk with a temperature of 8.45 degrees to be ŷ= 6.795 a)A 95% confidence interval for the mean pH of all milk with temperature 8.45 degrees is calculated to be (6.76, 6.83). Which of the following is the correct interpretation of this confidence interval? -The mean pH level for all glasses of milk having a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -The pH level for one glass of milk with a temperature of 8.45 degrees is somewhere between 6.76 and 6.83, with 95% confidence. -There is a probability of 0.95 that the mean pH level for this glass of milk with temperature 8.45 degrees is between 6.76 and 6.83. -95% of all glasses of milk with a temperature of 8.45 degrees have a pH level between 6.76 and 6.83. b)Suppose we have a glass of milk whose temperature is 8.45 degrees. We…
- A music manager wanted to construct a 95% confidence interval for the lenght of songs produced at his recording studio. Using data from a random sample of 47 songs, he obtained an interval of 3.05 < μ < 4.45. Which of the following is the correct interpretation of the interval? With 95% confidence, the mean width of all widgets is between 3.05 and 4.45. The mean width of all widgets is between 3.05 and 4.45, 95% of the time. We know this is true because the mean of our sample is between 3.05 and 4.45. There is a 95% chance that the mean of the population is between 3.05 and 4.45. With 95% confidence, the mean width of a randomly selected widget will be between 3.05 and 4.45. There is a 95% chance that the mean of a sample of 47 widgets will be between 3.05 and 4.45.A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?A survey was conducted that asked 1010 people how many books they had read in the past year, results indicated that bar x = 13.8 books and s=15.8 books. Construct a 95% confidence interval for the mean number of books people read. Round to three decimals
- A sociologist found that in a sample of 50 retired men, the average number of jobs they had during their lifetimes was 7.2. The population standard deviation is 2.1. a.) Find the 99% confidence interval of the mean number of jobs . b.) What is the point estimatorA certified mechanic was timed for the repair of an automobile on 14 separate occasions.Over the same period, a trainee mechanic was timed for the repair of a similar automobile.The times in minutes are given belowCertified 344 276 257 334 267 164 222 343 212 175 211 311 209 188Trainee 222 342 178 234 398 232 377 211 309 190 351 343 177 269a. Calculate a 99% confidence interval for the mean time taken to repair the automobile by the (i) certified mechanic and (ii) the trainee mechanic. b. Test the hypothesis that the two mean times for both mechanics are equal. Use the 5% level of significance. c. Subsequently, it was learned that the times for the trainee were incorrectly recorded and that each of the values above is 30 minutes too small. What, if any, the difference does this make to the results of the test done in part (d)?In a survey of 2490 golfers, 22% said they were left-handed. The survey's margin of error was 4%. Construct a confidence interval for the proportion of left-handed golfers. O (0.17, 0.27) (0.18, 0.26) ○ (0.18, 0.22) ○ (0.26, 0.30)
