Shamma computed a z-based confidence interval for the mean weight of ZU female students as (69.54, 73.46). Which of the following could be a t- based interval using the same data? O (69.789, 73.211) O (69.436, 73.564) O (69.54, 73.46) O (69.855, 73.145)
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- A large fishing operation takes a sample of 40 lobster pots and finds an average of 35 in each with a sample standard deviation of 10. What is the 95% confidence interval for the mean number of lobsters in each of the lobster pots? a. (86.34, 92.04) b. (53.06, 58.94) c. (175.69, 182.31) d. (31.90, 38.10) (89.86,94.14) е.A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 13 days following no advertisements, the mean was 23.9 purchasing customers with a standard deviation of 1.9 customers. On 6 days following advertising, the mean was 24.7 purchasing customers with a standard deviation of 1.6 customers. Test the claim, at the 0.01 level, that the mean number of customers who make a purchase in the store is lower for days following no advertising compared to days following advertising. Assume that both populations are approximately normal and that the population variances are equal. Let days following no advertisements be Population 1 and let days following advertising be Population 2. Step 1 of 3: State the…A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 11 days following no advertisements, the mean was 16.6 purchasing customers with a standard deviation of 1.1 customers. On 10 days following advertising, the mean was 17.7 purchasing customers with a standard deviation of 1.4 customers. Test the claim, at the 0.02 level, that the mean number of customers who make a purchase in the store is lower for days following no advertising compared to days following advertising. Assume that both populations are approximately normal and that the population variances are equal. Let days following no advertisements be Population 1 and let days following advertising be Population 2. Step 2 of 3 : Compute…
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- A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 10 days following no advertisements, the mean was 18.3 purchasing customers with a standard deviation of 1.8 customers. On 7 days following advertising, the mean was 19.4 purchasing customers with a standard deviation of 1.6 customers. Test the claim, at the 0.02 level, that the mean number of customers who make a purchase in the store is lower for days following no advertising compared to days following advertising. Assume that both populations are approximately normal and that the population variances are equal. Let days following no advertisements be Population 1 and let days following advertising be Population 2. Step 3 of 3: Draw a…Watch Corporation of Switzerland claims that its watches on average will neither gain nor lose time during a week. A sample of 18 watches provided the following gains (+) or losses (-) in seconds per week. Is it reasonable to conclude that the mean gain or loss in time for the watches is 0? 0.10 0.40 0.40 -0.32 0.20 -0.23 0.10 0.25 -0.10 -0.37 -0.61 0.00 -0.10 -0.64 0.00 -0.40 -0.68 -0.40 (a) State the decision rule for 0.02 significance level. (Negative amounts should be indicated by a minus sign) (Round your answers to 3 decimal places) Reject H0: μ = 0 if t < Answer or t > Answer (b) Compute the Value of the test statistic. (Negative amount should be indicated by a minus sign) (Round your answer to 2 decimal places) Test Statistic t= Answer (c) What is your decision regarding the null hypothesis? AnswerCannot Reject HoReject Ho Therefore the evidence supports the claim that AnswerH0: μ = 0H0: μ ≠ 0A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 7 days following no advertisements, the mean was 22.1 purchasing customers with a standard deviation of 1.2 customers. On 10 days following advertising, the mean was 24.1 purchasing customers with a standard deviation of 1.6 customers. Test the claim, at the 0.05 level, that the mean number of customers who make a purchase in the store is lower for days following no advertising compared to days following advertising. Assume that both populations are approximately normal and that the population variances are equal. Let days following no advertisements be Population 1 and let days following advertising be Population 2. Step 1 of 3: State the…