QUESTION 27Shamma computed a confidence interval for the mean weight of ZU female students based on a sample of size 40. The weights are not normallydistributed and Shamma used the Student's t distribution for the confidence interval instead of a normal distribution. Her interval isobtained by using an appropriate normal distribution................ oneshorter thansame aslarger thanNo enough information

It is given that the statement about to the confidence interval for t-distribution. Here, need to…

Answered: Shamma computed a confidence interval…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Prof. Gersch knows that the score on a standardized test is perfectly normal with unknown mean and a standard deviation of 50. He then takes a random sample of 25 tests and finds that the average of these is 200. How many exams should he sample so that the maximum margin of errorfor his 95% confidence interval is 10?: a. 98 b. 97 c. 100 d. 96 e. 10
Pedro was working on a report on Swiss and Austrian psychiatrists. He decided to find a 90 percent confidence interval for the difference in mean age at the time of significant psychiatric discoveries for Swiss versus Austrian psychiatrists. He found the ages at the time of psychological discovery of all the members of both groups and found the 90 percent confidence interval based on a t-distribution using a calculator. The procedure he used is not appropriate in this context because O The sample sizes for the two groups are not equal. O The entire population is measured in both cases, so the actual difference in means can be computed and a confidence interval should not be used. O Age at the time of psychological discovery occurs at different intervals in the two countries, so the distribution of ages cannot be the same. O Age at the time of psychological discovery is likely to be skewed rather than bell shaped, so the assumptions for using this confidence interval formula are not…
In order to estimate the percentage of adults who file their taxes at least two weeks be deadline, a 99% confidence interval is constructed. The interval ends up being from 0.756 to 0.864. Which of the following could be a 90% confidence interval for the same sample data? I. 0.749 to 0.871 II. 0.776 to 0.844 III. 0.765 to 0.875 IV. 0.799 to 0.841 OI only OIV only None of the answer options are reasonable 90% confidence intervals. III only O II only
Would it be skewed right since all the data would lie on the left side
Suppose a test is given to 20 randomly selected college freshmen in Ohio. The sample average score on the test is 12 points and the sample standard deviation is 4 points. Suppose the same test is given to 16 randomly selected college freshmen in Iowa. The sample average score on the test is 8 points and the sample standard deviation is 3 points. We want to test whether there is a significant difference in scores of college freshmen in Ohio versus Iowa. Does the 90% confidence interval indicate that there is evidence of a difference in population means? Group of answer choices Yes Not enough information No
Please show work
Do AP Statistics students have higher GPA's than non AP Statistics students? Random samples of 20 AP Statistics students and 20 non AP Statistic students were taken. AP Statistics students had a mean GPA of 3.335 with a standard deviation of 0.557. Non AP Statistics students had a mean GPA of 3.04 with a standard deviation of 0.685. Assume the distribution of all AP Statistics scores are normally distributed. Use a 95% confidence interval for the true difference in average GPAS for AP Statistics and non AP Statistics students to determine if one group has a higher GPA than the other.
Helga is researching the IQ of a particular monkey species. She measured the IQ in 15 monkeys with a special monkey IQ test and it turned out to be 120 points on average. The standard deviation was 12 points. It can be assumed that the IQ follows a normal distribution. What is the upper limit of the 95% confidence interval for the average monkey species index?
A team of researchers found that age distributions in a population of 100,000 people was not Normal. However, after they took a large number of simple random samples, each with (N=100), they observed that the sampling distribution of mean tended toward Normality. Really? Why is it possible?
Suppose a new standardized test is given to 97 randomly selected third-grade students in New Jersey. The sample average score Y on the test is 62 points, and the sample standard deviation, sy, is 10 points. The authors plan to administer the test to all third-grade students in New Jersey. The 95% confidence interval for the mean score of all New Jersey third graders is (60.01, 63.99). (Round your responses to two decimal places.) Suppose the same test is given to 194 randomly selected third graders from lowa, producing a sample average of 66 points and sample standard deviation of 13 points. The 90% confidence interval for the difference in mean scores between lowa and New Jersey is (-6.26 -1.74). (Round your responses to two decimal places.) The p-value of the test of no difference in means versus some difference is (Round your response to four decimal places.)

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