This is hourly data pertaining to the time it takes to serve a particular customer, in minutes. This data is sample data consisting of one customer sampled per hour. The manpower planning is based upon mean service time of 20.5 minutes. Is the manpower planning accurate (is it safe to say that the population mean service time could be 20.5 minutes)? This was great information but I need the confidence intervals for the mean and the standard error of the mean . I am trying to understand 95% confidence interval and the standard error of the mean . Please advise C21 21.8 21.9 21.7 21.6 21.7 21.7 21.4 21.5 21.4 21.9 21.8 21.8 21.6 21.5 21.9 21.7 21.8 21.4
This is hourly data pertaining to the time it takes to serve a particular customer, in minutes. This data is sample data consisting of one customer sampled per hour. The manpower planning is based upon
This was great information but I need the confidence intervals for the mean and the standard error of the mean . I am trying to understand 95% confidence interval and the standard error of the mean . Please advise
| C21 |
| 21.8 |
| 21.9 |
| 21.7 |
| 21.6 |
| 21.7 |
| 21.7 |
| 21.4 |
| 21.5 |
| 21.4 |
| 21.9 |
| 21.8 |
| 21.8 |
| 21.6 |
| 21.5 |
| 21.9 |
| 21.7 |
| 21.8 |
| 21.4 |
Expert Answer
Given,
Population mean = 20.5 minutes
Here we use t-test for testing of hypothesis
Testing of hypothesis are,
First, we calculate sample mean and sample standard deviation,
Test statistic is,
Degrees of freedom = n-1 = 18-1 = 17
Table value = 2.110 ……from t-test statistical table
Criteria: if t_cal > t_tab then we may reject H0 at 5% level of significance.
Conclusion: Here we may reject H0 at 5% level of significance. because t_cal =28.49 > t_tab = 2.110.
Interpretation: there is significant difference population mean
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