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Set up all the equations needed to use the systematic treatment of equilibria to solve for the pH of a 0.50 M solution of Na₂HASO. (Complete steps 1-4 for the systematic treatment). Step 1 Step 2 CEE) Na₂H AsOy →→ 2Na² + HASO4²- OK AS -> Ok 22 HASO₂²- = H² + ASO₂³- 3 HA₂O₂₂² + H₂O = H₂A₂O₁₂₁² + OH- OH" ) H₂ Aso₂₁² + H₂O = H₂A₂O₂ + 5+₂0= H² + OM" # All ag except +₂0 (2) * Step 3 [NG]² [HASO4²-] [NG₂ HASO₂] Ka= [H] [Asoy ³-] [+AsOy²] [OH-] [#₂ Asun] [HAsoy²-] ko K6= [OH-] [H₂ AsOu] [H₂ Asun] kw = [H] [OH-] [H₂0] CBE: [Na]²+ [++] = [HASO₂²] + [A₂U₂²³] + [H₂ A₂0₂] + [OH-] Step 4 MBE : FNA₂ HAJD4 = [NG₂HA₂Q₂] + 2 [HASU4,2]} + {H₂A50;'] + [H₂A30₂] + 3 [Asa, ³-] FNA₂ HASUY = 2 [Nat]

Set up all the equations needed to use the systematic treatment of equilibria to solve for the pH of a 0.50 M solution of Na₂HASO. (Complete steps 1-4 for the systematic treatment). Step 1 Step 2 CEE) Na₂H AsOy →→ 2Na² + HASO4²- OK AS -> Ok 22 HASO₂²- = H² + ASO₂³- 3 HA₂O₂₂² + H₂O = H₂A₂O₁₂₁² + OH- OH" ) H₂ Aso₂₁² + H₂O = H₂A₂O₂ + 5+₂0= H² + OM" # All ag except +₂0 (2) * Step 3 [NG]² [HASO4²-] [NG₂ HASO₂] Ka= [H] [Asoy ³-] [+AsOy²] [OH-] [#₂ Asun] [HAsoy²-] ko K6= [OH-] [H₂ AsOu] [H₂ Asun] kw = [H] [OH-] [H₂0] CBE: [Na]²+ [++] = [HASO₂²] + [A₂U₂²³] + [H₂ A₂0₂] + [OH-] Step 4 MBE : FNA₂ HAJD4 = [NG₂HA₂Q₂] + 2 [HASU4,2]} + {H₂A50;'] + [H₂A30₂] + 3 [Asa, ³-] FNA₂ HASUY = 2 [Nat]

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Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Set up all the equations needed to use the systematic treatment of equilibria to solve for the pH of a 0.50 M solution of Na₂HASO₂. (Complete steps 1-4 for the systematic treatment). Step 1 Step 2 CEE) Na₂H ASO₂ -> 2NG" Aso →→ 2NG" + HASO₂². Ok HASO4²- = H* + ASO ₂³- · HA₂O₂₂² + H₂0 = H₂₂A₂O₁₁² + OH- OH" · H₂Aso₁₁²³ + H₂O = H₂A₂Q₁₂₁ + 5 +₂₂0 = +* + OH' [NG]² [HASO4²-] [NG₂ HASO₂] Ka= [H] [AsOy ³-] [+AsOy²-] K₁0 = [OH-] [#1₂ Asu₂₂-] [HASO4²-] @ # All aq except +₂0 (2) * Step 3 K6= [OH-] [H₂Ason] [H₂ Asun] kw = [H+][OH-] [₂0] CBE: [Na]²+ [++] = [+ASO₁²] + [A$U₂³] + [H₂A₂0₂] + [OH-] Step 4 MBE: FNA₂HASO₂ = [Na₂HASQ₂] + 2 [HASUL₂²] + [#₂ AsO₁₂²] + [#₂ A₂0₁₂] + 3 [AsQ₂, ³-] Fua₂ HASUY = 2 [Nat]
Transcribed Image Text:Set up all the equations needed to use the systematic treatment of equilibria to solve for the pH of a 0.50 M solution of Na₂HASO₂. (Complete steps 1-4 for the systematic treatment). Step 1 Step 2 CEE) Na₂H ASO₂ -> 2NG" Aso →→ 2NG" + HASO₂². Ok HASO4²- = H* + ASO ₂³- · HA₂O₂₂² + H₂0 = H₂₂A₂O₁₁² + OH- OH" · H₂Aso₁₁²³ + H₂O = H₂A₂Q₁₂₁ + 5 +₂₂0 = +* + OH' [NG]² [HASO4²-] [NG₂ HASO₂] Ka= [H] [AsOy ³-] [+AsOy²-] K₁0 = [OH-] [#1₂ Asu₂₂-] [HASO4²-] @ # All aq except +₂0 (2) * Step 3 K6= [OH-] [H₂Ason] [H₂ Asun] kw = [H+][OH-] [₂0] CBE: [Na]²+ [++] = [+ASO₁²] + [A$U₂³] + [H₂A₂0₂] + [OH-] Step 4 MBE: FNA₂HASO₂ = [Na₂HASQ₂] + 2 [HASUL₂²] + [#₂ AsO₁₂²] + [#₂ A₂0₁₂] + 3 [AsQ₂, ³-] Fua₂ HASUY = 2 [Nat]
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