SET reg, immed ; 3 clock cycles LOAD reg, mem ;4 clock cycles ADD reg, reg ; 3 clock cycles ADD reg, immed ; 2 clock cycles LOOP _LabelName ; 8 clock cycles Assume that the following code fragment is used to sum the element of a numeric arn SET reg1, 0 SET reg2, MAX_SIZE ;initialize loop counter SET reg3, @list ;initialize array pointer ProcessArray: LOAD reg4, [reg3] ;fetch current list element ;initialize sum ADD ro1 road add current list olement

SET reg, immed ; 3 clock cycles LOAD reg, mem ;4 clock cycles ADD reg, reg ; 3 clock cycles ADD reg, immed ; 2 clock cycles LOOP _LabelName ; 8 clock cycles Assume that the following code fragment is used to sum the element of a numeric arn SET reg1, 0 SET reg2, MAX_SIZE ;initialize loop counter SET reg3, @list ;initialize array pointer ProcessArray: LOAD reg4, [reg3] ;fetch current list element ;initialize sum ADD ro1 road add current list olement

Name: Suppose you have a RISC machine with a 2.7 GHz clock (i.e., the clock
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Description: Suppose you have a RISC machine with a 2.7 GHz clock (i.e., the clock ticks 2.7 billion times per second).This particular computer uses an instruction cache, a data cache, an operand fetch unit, and an operandstore unit. The instruction set includes

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Flowchart, create. // Iterative C++ program to reverse an array #include <bits/stdc++.h> using namespace std; /* Function to reverse arr[] from start to end*/ void rvereseArray(int arr[], int start, int end) { while (start < end) { int temp = arr[start]; arr[start] = arr[end]; arr[end] = temp; start++; end--; } } /* Utility function to print an array */ void printArray(int arr[], int size) { for (int i = 0; i < size; i++) cout << arr[i] << " "; cout << endl; } /* Driver function to test above functions */ int main() { int arr[] = {90, 80, 70, 60, 50}; int n = sizeof(arr) / sizeof(arr[0]); cout<<"Original contents of array is:"<<endl; // To print original array printArray(arr, n); // Function calling rvereseArray(arr, 0, n-1); cout << "Reversed contents of array is" << endl; // To print the Reversed array printArray(arr,…
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The advantages of Array are as follows: Comparing the sizes of one-dimensional and two-dimensional arrays.
Language: C Topic: Arrays