Series pipe ABCD consists of 10,000 ft of 20′′, 8000 ft of 16′′, and L ft of 12′′ (C = 120). What length L will make the ABCD pipes equivalent to a 15′′ pipe, 16,500 ft long, C = 100? If the length of the 12′′ pipe from C to D were 3000 ft, what flow (in mgd) would occur for a lost head of 135 ft from A to D?

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A pipeline having a diameter of 250 mm has a rate of flow of 0.30 m³/sec. from point 1 to 2, with 2 lower than 1. A gate valve is connected at a point 3 near point 2. The elevation of point 2 is 100 m. O Compute the elevation of 1 when the gate valve at 3 is closed and the difference in pressure P2 - P1 = 78 КРа. ® Compute the head loss from 1 to 2 when the gate valve at 3 is open and the difference in pressure Ри- Р2%3D 160 kРа. 3 Compute the length of pipe from 1 to 2 if f = 0.020.

Pipes 1, 2 and 4 are connected in series with pipes 2 & 3 parallel to each other.Pipelines Diameter Length Friction Factor1 350mm 2500m 0.022 400mm 4000 m 0.023 300mm 2000 m 0.024 450mm 2500 m 0.02If the discharge of pipeline 2 is 0.05 m^3/s,1. Compute the rate of discharge of pipeline 32. Compute the rate of discharge of pipeline 43. Compute the total headloss of the pipe system

A 6-inch-diameter pipeline has a length of 845 ft and flows between two reservoirs with an elevation drop of 33.5 ft. The pipe is ductile iron and the fluid is water at 40° F. Minor losses are listed below. Description Number 90° Bends 9 45° Bends 8 Other R/d=2.5 R/d=5 Gate Valves 4 Fully Open Swing-Check Valves 2 Entrance 1 Square Edge Exit a. Determine the flow rate using the Darcy-Weisbach equation and the fully rough friction factor from the Moody Diagram. Neglect minor losses for this flow estimate. b. Modify the friction factor using the Reynolds number from the flow above. Include minor losses using K values from the class handout. Recompute the flow rate. c. Using the friction factor from (a), convert the minor losses to an equivalent pipe length and use the Swamee-Jain equation for Q to estimate the flow rate. d. Convert the minor losses to an equivalent pipe length for the Hazen-Williams equation. Use a C = 140 and calculate the flow rate by adding the minor loss equivalent…

A discharge of 600 liters/sec. flows through a pipe having a diameter of 400 mm Ø. length of 40 m. long, compute the head loss of the pipeline using: Mannings Equation with n = 0.013 a) 1.39 m. b) 2.84 m. c) 3.32 m. d) 4.47 m. - @Darcy Weishback f = 0.012. a) 1.39 m. b) 2.84 m. - Hazen C = 100. a) 1.39 m. b) 2.84 m. Williams formula with c) 3.32 m. d) 4.47 m. Formula with c) 3.32 m. d) 4.47 m.

Situation 2 Pipelines 1,2, and 3 are connected parallel to each other. The three pipes carry a combined discharge of 0.86 m/s. 1 Pipe Length Diameter Friction Factor 1,800 mm 1,500 mm 2,000 mm 0.020 0.018 0.022 400 mm A 2 в у 350 mm 3 300 mm 3 4. Determine the flow rate through pipeline 1 (Q1) in m3/s. 5. Determine the flow rate through pipeline 2 (Q2) in m3/s 6. Determine the flow rate through pipeline 3 (Q3) in m3/s

Pipelines 1, 2, and 3 are connected with parallel to each other with pipeline 1 having diameter of 884 mm, 797 m. long, pipeline 2, 608 mm diameter, 845 m long ad pipeline 3, 641 mm diameter, 773 m long. The 3 pipes carry a combined discharge of 0.993 m3/s. Assuming f = 0.055 for all pipes. Compute the head loss of pipeline 3 in m. Round 3 decimal places

A 300 mm-dia 5000m long is connected between two reservoirs A and B having water surface elevations at 150m and 100m, respectively.  To increase the capacity of the old pipeline, a 300mm-dia pipeline 2500m long is laid out from the original pipeline at its mid-point towards reservoir B.  Assuming f=0.027 for all pipes, what would be the increase in flow by installing the new pipeline? Neglect minor losses.