Chapter AssessmentsI Series-Parallel Circuit AnalysisA. Solve for the required values with complete solution and progressive simplified circuits.Box the final answer for the required values.1. In Fig. 4.19, solve for Ry, Ir, l2, I4, and PR, = 75 0R= 150 2V,- 12 VR-330 0R- 180 1Figure 4.192. For each of the circuits shown in Fig. 4.20,a. find the equivalent resistance seen by the source,b. find the power developed by the source.210 0280 N100120Ω180Ω:१15 0 90 V/40 Ω30 mA (200 225 0(a)(b)Figure 4.203. For the network in Fig. 4.21Note: E is also equivalent to the designation Vs or Vr for voltage source and Is isequivalent to lr for total current of the circuit being analyzed.a. Find currents Is, I2, and 16.b. Find voltages V1 and Vs.c. Find the power delivered to the 3 ka resistor.

Answered: Image /qna-images/answer/61d998a3-2dce-4035-a2da-20eedaca8e37.jpg

Series-Parallel Circuit Analysis A. Solve for the required values with complete solution and progressive simplified circuits. Box the final answer for the required values. 1. In Fig. 4.19, solve for R7, IT, l2, 14, and P I. R, = 75 0 R = 150 2 V,- 12V: A-330 a R- 180 0 Figure 4.19

Series-Parallel Circuit Analysis A. Solve for the required values with complete solution and progressive simplified circuits. Box the final answer for the required values. 1. In Fig. 4.19, solve for R7, IT, l2, 14, and P I. R, = 75 0 R = 150 2 V,- 12V: A-330 a R- 180 0 Figure 4.19

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

Chapter Assessments
I Series-Parallel Circuit Analysis
A. Solve for the required values with complete solution and progressive simplified circuits.
Box the final answer for the required values.
1. In Fig. 4.19, solve for Ry, Ir, l2, I4, and P
R, = 75 0
R= 150 2
V,- 12 V
R-330 0
R- 180 1
Figure 4.19
2. For each of the circuits shown in Fig. 4.20,
a. find the equivalent resistance seen by the source,
b. find the power developed by the source.
210 0
280 N
100
120Ω180Ω:
१15 0 90 V/
40 Ω
30 mA (
200 2
25 0
(a)
(b)
Figure 4.20
3. For the network in Fig. 4.21
Note: E is also equivalent to the designation Vs or Vr for voltage source and Is is
equivalent to lr for total current of the circuit being analyzed.
a. Find currents Is, I2, and 16.
b. Find voltages V1 and Vs.
c. Find the power delivered to the 3 ka resistor.

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