1 equation supernode: v1+ lb + equation node 4: v1+ lb + v1+ equation from supernode: equation for va: v1+ Answers for P4.4-14 (Remember a coefficient can be zero.) equation node 1: v1 + ib+ equation for ib: v2+ v1+ 16+ 1022 3ib 25 V = 0 =0 v2+v3+ =0 v2-3v3+ 4 =0 v2-v3+ v2+ = 0 √3+ [ =0 v2+ v3+ 50₂ 2002 ww 30 92 ib 2A(1 v4+ ]v4+ [ ]v4+ [ v4+ v3+v4- v4+ [ 3 Va+ Va+ Va Va+ Va+ Va+

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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+
equation supernode:
v1+
+
equation node 4:
v1 +
+
Answers for P4.4-14 (Remember a coefficient can be zero.)
equation node 1:
v1 +
v1 +
equation from supernode:
equation for va:
equation for ib:
v1 +
ib+
v2+
v1 +
16+
10 22
3ib
25 V
= 0
=0
v2 + v3
=0
v2-3v3+
= 0
v2-v3+
Va 30 92
v3+
v2 +
=0
|=0
50₂
v2 + v3+
+
202 ib
2A(1
v4+
v4+
V4 +
V4 +
v3+v4+
v4+
3
Va
Va+
Va
Va+
+
V₂ +
Va
Transcribed Image Text:+ equation supernode: v1+ + equation node 4: v1 + + Answers for P4.4-14 (Remember a coefficient can be zero.) equation node 1: v1 + v1 + equation from supernode: equation for va: equation for ib: v1 + ib+ v2+ v1 + 16+ 10 22 3ib 25 V = 0 =0 v2 + v3 =0 v2-3v3+ = 0 v2-v3+ Va 30 92 v3+ v2 + =0 |=0 50₂ v2 + v3+ + 202 ib 2A(1 v4+ v4+ V4 + V4 + v3+v4+ v4+ 3 Va Va+ Va Va+ + V₂ + Va
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