Sereja likes to hang around trees. A tree is an undirected graph on N vertices with N-1 edges and no cycles. Sereja has his own peculiar way of comparing two trees. To describe it, let's start with the way Sereja stores a tree. For every tree, Sereja has a value V– the root of the tree, and for every vertex i, he has an ordered list Qli] with L[i] elements – Qli[1], Qi[2], .., QIJLO] which are children of the vertex i. Sereja assumes two trees to be equal if their roots are the same and for every i, the ordered list Q[i] is the same in both the trees that Sereja compares. So if Sereja has tree#1 given as [V=1, Q[1]=[2, 3], Q[2]=[], Q[3]=0] and tree#2 given as [V=1, Q[1]=[3, 2], Q[2]=0, Q[3]=[]], they will be considered different because Q[1] in the first tree is not equal to Q[1] in the second tree. For any vertex i, Sereja calls number of vertices adjacent to it as E[i]. Given an array C of N elements, Let f(C) be the number of different trees (in Sereja's representation) such that there exists a permutation P[1], P[2], .. , P[N] so that E[P[1]]=C[1], E[P[2]]= C[2], ... , E[P[N]]=C[N]. Sereja gives you the array C. You have to compute the number f(C) modulo 1000000007 (109+7).
Sereja likes to hang around trees. A tree is an undirected graph on N vertices with N-1 edges and no cycles. Sereja has his own peculiar way of comparing two trees. To describe it, let's start with the way Sereja stores a tree. For every tree, Sereja has a value V– the root of the tree, and for every vertex i, he has an ordered list Qli] with L[i] elements – Qli[1], Qi[2], .., QIJLO] which are children of the vertex i. Sereja assumes two trees to be equal if their roots are the same and for every i, the ordered list Q[i] is the same in both the trees that Sereja compares. So if Sereja has tree#1 given as [V=1, Q[1]=[2, 3], Q[2]=[], Q[3]=0] and tree#2 given as [V=1, Q[1]=[3, 2], Q[2]=0, Q[3]=[]], they will be considered different because Q[1] in the first tree is not equal to Q[1] in the second tree. For any vertex i, Sereja calls number of vertices adjacent to it as E[i]. Given an array C of N elements, Let f(C) be the number of different trees (in Sereja's representation) such that there exists a permutation P[1], P[2], .. , P[N] so that E[P[1]]=C[1], E[P[2]]= C[2], ... , E[P[N]]=C[N]. Sereja gives you the array C. You have to compute the number f(C) modulo 1000000007 (109+7).
Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Chapter1: Computer Networks And The Internet
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Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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![Sereja likes to hang around trees. A tree is an undirected graph on N vertices with
N-1 edges and no cycles. Sereja has his own peculiar way of comparing two trees.
To describe it, let's start with the way Sereja stores a tree. For every tree, Sereja
has a value V– the root of the tree, and for every vertex i, he has an ordered list
Q[i] with L[i] elements – Q[i][1], Q[i][2], ..., Q[iLI] which are children of the
vertex i. Sereja assumes two trees to be equal if their roots are the same and for
every i, the ordered list Q[i] is the same in both the trees that Sereja compares.
So if Sereja has tree#1 given as [V=1, Q[1]=[2, 3], Q[2]=[], Q[3]=0] and tree#2
given as [V=1, Q[1]=[3, 2], Q[2]=[], Q[3]=[]], they will be considered different
because Q[1] in the first tree is not equal to Q[1] in the second tree.
For any vertex İ, Sereja calls number of vertices adjacent to it as E[i).
Given an array C of N elements, Let f(C) be the number of different trees (in
Sereja's representation) such that there exists a permutation P[1], P[2], ... , P[N]
so that E[P[1]]=C[1], E[P[2]]= C[2], ... , E[P[N]]=C[N].
Sereja gives you the array C. You have to compute the number f(C) modulo
1000000007 (109+7).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F65ff17fc-9930-48d4-b362-f8b1ecec941f%2Fe6d0b1c2-4a94-4314-af88-d7177e814cd1%2Fjk94zu6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Sereja likes to hang around trees. A tree is an undirected graph on N vertices with
N-1 edges and no cycles. Sereja has his own peculiar way of comparing two trees.
To describe it, let's start with the way Sereja stores a tree. For every tree, Sereja
has a value V– the root of the tree, and for every vertex i, he has an ordered list
Q[i] with L[i] elements – Q[i][1], Q[i][2], ..., Q[iLI] which are children of the
vertex i. Sereja assumes two trees to be equal if their roots are the same and for
every i, the ordered list Q[i] is the same in both the trees that Sereja compares.
So if Sereja has tree#1 given as [V=1, Q[1]=[2, 3], Q[2]=[], Q[3]=0] and tree#2
given as [V=1, Q[1]=[3, 2], Q[2]=[], Q[3]=[]], they will be considered different
because Q[1] in the first tree is not equal to Q[1] in the second tree.
For any vertex İ, Sereja calls number of vertices adjacent to it as E[i).
Given an array C of N elements, Let f(C) be the number of different trees (in
Sereja's representation) such that there exists a permutation P[1], P[2], ... , P[N]
so that E[P[1]]=C[1], E[P[2]]= C[2], ... , E[P[N]]=C[N].
Sereja gives you the array C. You have to compute the number f(C) modulo
1000000007 (109+7).
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