Self-test 16.2 A CH₂Cl molecule has a C-Cl bond length of 178 pm, a C-H bond length of 111 pm, and an HCH angle of 110.5°. Calculate its rotational energy terms. [F(J, K)/cm¹ = 0.444J (J + 1) + 4.58K²; also F(J, K)/GHz = 13.3J (J + 1) + 137K²]
Self-test 16.2 A CH₂Cl molecule has a C-Cl bond length of 178 pm, a C-H bond length of 111 pm, and an HCH angle of 110.5°. Calculate its rotational energy terms. [F(J, K)/cm¹ = 0.444J (J + 1) + 4.58K²; also F(J, K)/GHz = 13.3J (J + 1) + 137K²]
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![Self-test 16.2 A CH335Cl molecule has a C-Cl bond length of 178 pm, a
C-H bond length of 111 pm, and an HCH angle of 110.5°. Calculate its
rotational energy terms.
[F(J, K)/cm¹ = 0.444J (J + 1) + 4.58K²;
also F(J, K)/GHz = 13.3J (J + 1) + 137K²]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F581d3e1e-0870-4230-bf1e-d899f30231e1%2Fd2db432e-bc19-48a4-bc38-311156a3f93f%2Fh3xu5x9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Self-test 16.2 A CH335Cl molecule has a C-Cl bond length of 178 pm, a
C-H bond length of 111 pm, and an HCH angle of 110.5°. Calculate its
rotational energy terms.
[F(J, K)/cm¹ = 0.444J (J + 1) + 4.58K²;
also F(J, K)/GHz = 13.3J (J + 1) + 137K²]
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