Self inductance of an inductor with toroidal geometry is 268 mH. The total number of turns of this inductor is 36. If a current of 28 A flows through the inductor, calculate its total magnetic flux in units of mWb. Answer:

Self inductance of an inductor with toroidal geometry is 268 mH. The total number of turns of this inductor is 36. If a current of 28 A flows through the inductor, calculate its total magnetic flux in units of mWb. Answer:

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Question

Self inductance of an inductor with toroidal
geometry is 268 mH. The total number of
turns of this inductor is 36. If a current of 28
A flows through the inductor, calculate its
total magnetic flux in units of mWb.
Answer:

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