Self inductance of an inductor with toroidal geometry is 268 mH. The total number of turns of this inductor is 36. If a current of 28 A flows through the inductor, calculate its total magnetic flux in units of mWb. Answer:

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Self inductance of an inductor with toroidal
geometry is 268 mH. The total number of
turns of this inductor is 36. If a current of 28
A flows through the inductor, calculate its
total magnetic flux in units of mWb.
Answer:
Transcribed Image Text:Self inductance of an inductor with toroidal geometry is 268 mH. The total number of turns of this inductor is 36. If a current of 28 A flows through the inductor, calculate its total magnetic flux in units of mWb. Answer:
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