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Select the major product of the following reaction. H3O+ H2O Тон OH ? OH HO.

Select the major product of the following reaction. H3O+ H2O Тон OH ? OH HO.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter22: Organic And Biological Molecules
Section: Chapter Questions
Problem 132AE
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Question
**Title:** Determining the Major Product of an Alkene Hydration Reaction **Reaction:** The chemical reaction involves an alkene reacting with hydronium ion (\(H_3O^+\)) in the presence of water (\(H_2O\)) to yield an alcohol. Below is the depiction of the reaction: - **Reactant:** The alkene presented is 2-methylpropene. - **Reagents:** \(H_3O^+\) and \(H_2O\). This reaction is an example of acid-catalyzed hydration of an alkene, typically following Markovnikov's rule for the addition of water. **Possible Products:** There are four potential alcohol products shown below: 1. 2-methyl-2-propanol 2. 2-butanol 3. 3-methyl-2-butanol 4. 2-methyl-1-propanol **Explanation of Reaction and Markovnikov's Rule:** Markovnikov's rule states that in the addition of HX to an alkene, the hydrogen atom attaches to the carbon with more hydrogen atoms, and the halide (or in this case, the OH group from the water) attaches to the carbon with fewer hydrogen atoms. **Conclusion:** According to Markovnikov's rule, the expected major product of the given reaction is 2-methyl-2-propanol, which places the hydroxyl group on the more substituted carbon atom in the reactant alkene, resulting in a tertiary alcohol.
Transcribed Image Text:**Title:** Determining the Major Product of an Alkene Hydration Reaction **Reaction:** The chemical reaction involves an alkene reacting with hydronium ion (\(H_3O^+\)) in the presence of water (\(H_2O\)) to yield an alcohol. Below is the depiction of the reaction: - **Reactant:** The alkene presented is 2-methylpropene. - **Reagents:** \(H_3O^+\) and \(H_2O\). This reaction is an example of acid-catalyzed hydration of an alkene, typically following Markovnikov's rule for the addition of water. **Possible Products:** There are four potential alcohol products shown below: 1. 2-methyl-2-propanol 2. 2-butanol 3. 3-methyl-2-butanol 4. 2-methyl-1-propanol **Explanation of Reaction and Markovnikov's Rule:** Markovnikov's rule states that in the addition of HX to an alkene, the hydrogen atom attaches to the carbon with more hydrogen atoms, and the halide (or in this case, the OH group from the water) attaches to the carbon with fewer hydrogen atoms. **Conclusion:** According to Markovnikov's rule, the expected major product of the given reaction is 2-methyl-2-propanol, which places the hydroxyl group on the more substituted carbon atom in the reactant alkene, resulting in a tertiary alcohol.
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