Select the integral equation that represents the shaded area in terms of f(x) and g(x). O °*If(x) — 9(2)]dx + f(x) - 9(x)\dx + [Description of Image: Downward parabola between x = -2 and x-6. Line from (-2, 0) through (2, 4), points where the line intersects the parabola. Shaded area P is to the left of the line, below the parabola, and above the x-axis.] Lif(z)- f(x) (2.4) [ƒ(2) – 9(x)]dx << Previous P f(x)dz 6 + g(x)]dx + [ f(x)dx f(x) dx y = f(r) No

Calculus: Early Transcendentals
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Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Select the integral equation that represents the shaded area in terms of f(x) and g(x).
Question 26
O
[Description of Image: Downward parabola between x = -2 and x=6. Line from (-2, 0) through (2, 4), points where the line
intersects the parabola. Shaded area P is to the left of the line, below the parabola, and above the x-axis.]
2.
Lif(a)-9
D
◄ Previous
A
O
°S ²[ƒ(x) − 9(x)]dx +
O
° S , [ƒ(2) – 9(z)]dx
) — 9(2)]dz +
R
:ST)
O
° S*_\ƒ(x) + g(x)\dx + [ª f(x)dx
N
NO
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2
F2
²
W
(2,4)
K
S
+
.
f(x)dx
+6₂º.
X
f(x) dx
# 3
80
F3
E
-
y = f(x)
D
64 +
4
C
20
R
LL
do 50
%
T
V
MacBook Air
6
G
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No
Transcribed Image Text:Select the integral equation that represents the shaded area in terms of f(x) and g(x). Question 26 O [Description of Image: Downward parabola between x = -2 and x=6. Line from (-2, 0) through (2, 4), points where the line intersects the parabola. Shaded area P is to the left of the line, below the parabola, and above the x-axis.] 2. Lif(a)-9 D ◄ Previous A O °S ²[ƒ(x) − 9(x)]dx + O ° S , [ƒ(2) – 9(z)]dx ) — 9(2)]dz + R :ST) O ° S*_\ƒ(x) + g(x)\dx + [ª f(x)dx N NO @ 2 F2 ² W (2,4) K S + . f(x)dx +6₂º. X f(x) dx # 3 80 F3 E - y = f(x) D 64 + 4 C 20 R LL do 50 % T V MacBook Air 6 G si Y B & 7 S H C 00 8 N 4 F No
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