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Select the correct program that give 1 in the output #include void main(){ int i j=%; for(i=0;i<5;i++) j=j+2*i j=j%3)-1%; printf("%d",j);} #include void main(){ int i j=%; for(i=7;i>0;i--) j=j+i j=j/3)-1; printf(“%d",j);} O Option 2 #include #include void main(){ int i j=0; for(i=1;i<6;i++) j=j* 2+i j=G/3); printf("%d",j);} void main(){ int i j=0; for(i=0;i<5;i++) j=j+2*i j=j/3)+1; printf("%d",j);}

Select the correct program that give 1 in the output #include void main(){ int i j=%; for(i=0;i<5;i++) j=j+2*i j=j%3)-1%; printf("%d",j);} #include void main(){ int i j=%; for(i=7;i>0;i--) j=j+i j=j/3)-1; printf(“%d",j);} O Option 2 #include #include void main(){ int i j=0; for(i=1;i<6;i++) j=j* 2+i j=G/3); printf("%d",j);} void main(){ int i j=0; for(i=0;i<5;i++) j=j+2*i j=j/3)+1; printf("%d",j);}

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Select the correct program that give 1 in the output #include<stdio.h> void main(){ int i j=0; for(i=0;i<5;i++) 月+2* j=j%3)-1%; printf("%d",j);} #include<stdio.h> void main(){ int i j=0; for(i=7;i>0;i--) j=j+i j=G/3)-1; printf(“%d",j);} O Option 2 #include<stdio.h> #include<stdio.h> void main(){ int i j=0; for(i=1;i<6;i++) j=j*2+i j=j/3); printf("%d",j);} void main(){ int i j=0; for(i=0;i<5;i++) j=j+2*i j=(j/3)+1; printf("%d",j);}
Transcribed Image Text:Select the correct program that give 1 in the output #include<stdio.h> void main(){ int i j=0; for(i=0;i<5;i++) 月+2* j=j%3)-1%; printf("%d",j);} #include<stdio.h> void main(){ int i j=0; for(i=7;i>0;i--) j=j+i j=G/3)-1; printf(“%d",j);} O Option 2 #include<stdio.h> #include<stdio.h> void main(){ int i j=0; for(i=1;i<6;i++) j=j*2+i j=j/3); printf("%d",j);} void main(){ int i j=0; for(i=0;i<5;i++) j=j+2*i j=(j/3)+1; printf("%d",j);}
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