* Find the result of the following program#include #includeVoid main(void)float r, h, t;h=30.0; t-8.0%3Br=(5+2*h)/t;cout<

Define header files <iostream> and <iomanip> for io and manipulation of data operations.…

Answered: * Find the result of the following…

Engineering

Computer Science

* Find the result of the following program

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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#include using namespace std; void myfunction(int num2, int num1); lint main() { my function (5,2); return 0; } void myfunction(int num1, int num2) {if (num1>3) cout << "A1"; else if (num1<3) cout<<"A2"; else cout<<"A3";} O A2 O A1 O A3 A1 A2 A3
#include using namespace std; int main() int x=1,y=2; for (int i=0; i<3; i++) e{ x=x*y; 8{ } cout<
#include <stdio.h>void cubeByReference( int *nPtr ); // function prototypeint main( void ){ int number = 5; // initialize number printf("The original value of number is %d", number ); // pass address of number to cubeByReference cubeByReference( &number ); printf("\nThe new value of number is %d\n", number );} // end main void cubeByReference( int *nPtr ){ *nPtr = *nPtr* *nPtr* *nPtr;} passing argument by reference - We modify the code above 1- define a second argument (example "int number2 = 9") and a pointer to it 2- define a second function (addByReference) that adds number2 to number - passing both arguments by reference 3- print-out the result (that is in number) Upload the output and .c code
#include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05);cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…
#include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05); cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…
#include <stdio.h>#include <stdlib.h> int cent50 = 0;int cent20 = 0;int cent10 = 0;int cent05 = 0; //Function definitionvoid calculateChange(int change) {if(change > 0) {if(change >= 50) {change -= 50;cent50++;} else if(change >= 20) {change -= 20;cent20++;} else if(change >= 10) {change -= 10;cent10++;} else if(change >= 05) {change -= 05;cent05++;}calculateChange(change);}} //Define the functionvoid printChange() { if(cent50)printf("\n50 Cents : %d coins", cent50); if(cent20)printf("\n20 Cents : %d coins", cent20); if(cent10)printf("\n10 Cents : %d coins", cent10); if(cent05)printf("\n05 Cents : %d coins", cent05);cent50 = 0;cent20 = 0;cent10 = 0;cent05 = 0; } //Function's definitionint TakeChange() { int change;printf("\nEnter the amount : ");scanf("%d", &change);return change; }//main functionint main() {//call the functionint change = TakeChange(); //use while-loop to repeatedly ask for input to the userwhile(change != -1){if((change %…
#include<iostream>using namespace std;void main(){double pi = 0, denominator = 1;int counter = 999999;for (int x = 0; x < counter; x++){if (x % 2 != 0){pi = pi - (1 / denominator);}else{pi = pi + (1 / denominator);}denominator = denominator + 2;}pi = pi * 4;cout << " So the computed value of a PI is = " << pi << endl;cout << " ";//return 0;system("pause");} Note: This a program called ComputePI to compute the value of π Tutor just have to Modify This program to use nested-if (if ... else if ... else if ... else) instead. Explain by applying a double line comment
#include void main(void) { int c =2 ^3; cout<< c; }
C++ Functions provide a means to modularize applications Write a function called "Calculate" takes two double arguments returns a double result For example, the following is a function that takes a single "double" argument and returns a "double" result double squareArea(double side){ double lArea; lArea = side * side; return lArea;}
1#include 2 #include #include 4 #include 3 5 sem_t fork[3]; 6 7 void eat (int phil) { 8 printf("Philosopher %d is eating\n", phil); sleep (2); //time eating 9 10} 11 void philosopher (void * num) { int phil-*(int *)num; 12 13 printf("Philosopher %d wants to eat\n", phil); 14 sem_wait (&fork[phil]); 15 sem_wait (&fork [(phil+1)]); 16 eat (phil); 17 18 printf("Philosopher %d has finished eating\n",phil); sem_post(&fork [(phil+1)]); sem_post(&fork[phil]); 19 20} 21 int main(){ 22 int i, a[3]; 23 pthread_t tid[3]; for(i=0;i<3; i++) 24 25 sem_init(&fork[i],0,1); 26 for(i=0;i<3; i++){ 27 a[i]=i; 28 pthread_create(&tid[i], NULL, philosopher, (void *)&a[i]); 29 } 30 for(i=0;i<3;i++) 31 pthread_join(tid[i],NULL); 32} Fig.1 Figure 1 shows a program that tries to solve the dining philosophers' problem given that it only includes 3 philosophers who want to eat, where only 3 forks are available and each philosopher needs two forks. The outputs after running the program are given in Figure 2. In the…
#include using namespace std; void some_action_1(int); int main() { cout<
This is the C code I have so far #include <stdio.h> #include <stdlib.h> struct employees { char name[20]; int ssn[9]; int yearBorn, salary; }; // function to read the employee data from the user void readEmployee(struct employees *emp) { printf("Enter name: "); gets(emp->name); printf("Enter ssn: "); for (int i = 0; i < 9; i++) scanf("%d", &emp->ssn[i]); printf("Enter birth year: "); scanf("%d", &emp->yearBorn); printf("Enter salary: "); scanf("%d", &emp->salary); } // function to create a pointer of employee type struct employees *createEmployee() { // creating the pointer struct employees *emp = malloc(sizeof(struct employees)); // function to read the data readEmployee(emp); // returning the data return emp; } // function to print the employee data to console void display(struct employees *e) { printf("%s", e->name); printf(" %d%d%d-%d%d-%d%d%d%d",…