Select the correct answer. Triangle XYZ has an altitude of h. Jayden proves the area of AXYZ using trigonometry. His work is shown. Y h b a y The area of AXYZ is Zyh by the definition of the area of a triangle. Using the sine ratio, 81n(X) = 7. Also, *3in(X) = h is true by the multiplication property of equality. So, by the substitution property of equality, the area of AXYZ is Where did Jayden make his first error in the proof? O A. The area of AXYZ İs incorrect. It should be ah. OB. The sine ratio sin(X) = is incorrect. It should be sin(Y) = . Oc. The area of AXYZ İs incorrect. It should be O D. The sine ratio sin(X) = is incorrect. It should be gin(Z) =
Select the correct answer. Triangle XYZ has an altitude of h. Jayden proves the area of AXYZ using trigonometry. His work is shown. Y h b a y The area of AXYZ is Zyh by the definition of the area of a triangle. Using the sine ratio, 81n(X) = 7. Also, *3in(X) = h is true by the multiplication property of equality. So, by the substitution property of equality, the area of AXYZ is Where did Jayden make his first error in the proof? O A. The area of AXYZ İs incorrect. It should be ah. OB. The sine ratio sin(X) = is incorrect. It should be sin(Y) = . Oc. The area of AXYZ İs incorrect. It should be O D. The sine ratio sin(X) = is incorrect. It should be gin(Z) =
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter1: Fundamental Concepts Of Algebra
Section1.1: Real Numbers
Problem 45E
Related questions
Question
![Select the correct answer.
Triangle XYZ has an altitude of h. Jayden proves the area of AXYZ using trigonometry. His work is shown.
Y
h
b
a
y
The area of AXYZ is Zyh by the definition of the area of a triangle. Using the sine ratio, 81n(X) = 7. Also, *3in(X) = h is true by the
multiplication property of equality. So, by the substitution property of equality, the area of AXYZ is
Where did Jayden make his first error in the proof?
O A.
The area of AXYZ İs incorrect. It should be ah.
OB.
The sine ratio sin(X) = is incorrect. It should be sin(Y) = .
Oc.
The area of AXYZ İs incorrect. It should be
O D.
The sine ratio sin(X) = is incorrect. It should be gin(Z) =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F92eef510-6590-48f8-bd3d-e49d40277c3e%2F8f120ca1-c666-4820-b9d9-6df4ae23fc9a%2Fd6jisr_processed.png&w=3840&q=75)
Transcribed Image Text:Select the correct answer.
Triangle XYZ has an altitude of h. Jayden proves the area of AXYZ using trigonometry. His work is shown.
Y
h
b
a
y
The area of AXYZ is Zyh by the definition of the area of a triangle. Using the sine ratio, 81n(X) = 7. Also, *3in(X) = h is true by the
multiplication property of equality. So, by the substitution property of equality, the area of AXYZ is
Where did Jayden make his first error in the proof?
O A.
The area of AXYZ İs incorrect. It should be ah.
OB.
The sine ratio sin(X) = is incorrect. It should be sin(Y) = .
Oc.
The area of AXYZ İs incorrect. It should be
O D.
The sine ratio sin(X) = is incorrect. It should be gin(Z) =
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