Select reagents from the table to perform the following conversions. Enter your answer as a string of letters in the order that you wish to use the reagents, i.e. bde. Do not use punctuation. Reagents available f. H₂, Pd/C g. (sia)2 BH then H₂O2, NaOH h. BH3 then H₂O2, NaOH d. Na, i. excess NaNH2, then H₂O NH3 (1) e. H₂, Lindlar's catalyst j. H₂SO4, H₂O, HgSO4 a. Br2, CCl4 b. excess NaNH, c. CH3 I Conversion #1: Conversion #2:

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Select reagents from the table to perform the following conversions.
Enter your answer as a string of letters in the order that you wish to use the reagents, i.e. bde. Do not use punctuation.
a. Br₂, CCl4
b. excess NaNH,
c. CH3 I
d.
Na,
NH3 (1)
e. H₂, Lindlar's catalyst j. H₂SO4, H₂O, HgSO4
Conversion #1:
Reagents available
f. H₂, Pd/C
g. (sia)2BH then H₂O2, NaOH
h. BH3 then H₂O2, NaOH
Conversion #2:
i. excess NaNH₂, then H₂O
Transcribed Image Text:Select reagents from the table to perform the following conversions. Enter your answer as a string of letters in the order that you wish to use the reagents, i.e. bde. Do not use punctuation. a. Br₂, CCl4 b. excess NaNH, c. CH3 I d. Na, NH3 (1) e. H₂, Lindlar's catalyst j. H₂SO4, H₂O, HgSO4 Conversion #1: Reagents available f. H₂, Pd/C g. (sia)2BH then H₂O2, NaOH h. BH3 then H₂O2, NaOH Conversion #2: i. excess NaNH₂, then H₂O
Expert Solution
Step 1: Formation of higher alkene

The given alkenes are converted into higher alkene. The reaction proceeds in the following steps:

  • For this first of all the alkene is converted into alkyne
  • Then alkylation of alkyne
  • Then reduction of alkyne into alkene.
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