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Select R, and R2 such that vo 7.5vs o a + vo Vs R2 R1 o b

Select R, and R2 such that vo 7.5vs o a + vo Vs R2 R1 o b

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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The diagram illustrates an inverting amplifier configuration using an operational amplifier. The circuit is tasked with selecting resistors \( R_1 \) and \( R_2 \) such that the output voltage \( v_o \) equals 7.5 times the source voltage \( v_s \). ### Diagram Explanation: 1. **Voltage Source (\( v_s \))**: - Denoted by a circle with a positive and negative sign, indicating the input voltage to the amplifier circuit. 2. **Operational Amplifier**: - Depicted by a triangle with a positive (+) and negative (-) input terminal. - **Inverting Input (-)**: The line connecting this terminal is linked to the node between \( R_1 \) and \( R_2 \). - **Non-inverting Input (+)**: This terminal is connected to the voltage source \( v_s \). 3. **Resistors**: - **\( R_1 \)**: Connected between the inverting input and ground. - **\( R_2 \)**: Connected between the inverting input and the output of the operational amplifier. 4. **Output Voltage (\( v_o \))**: - Represented at the output terminal of the operational amplifier. - The voltage \( v_o \) is directed towards terminals \( a \) and \( b \), with \( a \) being positive and \( b \) being negative. ### Target Equation: - The output voltage equation describes the relationship: \( v_o = - \left( \frac{R_2}{R_1} \right) v_s \). - To achieve \( v_o = 7.5v_s \), the resistances \( R_1 \) and \( R_2 \) must be selected such that \( \frac{R_2}{R_1} = 7.5 \).
Transcribed Image Text:The diagram illustrates an inverting amplifier configuration using an operational amplifier. The circuit is tasked with selecting resistors \( R_1 \) and \( R_2 \) such that the output voltage \( v_o \) equals 7.5 times the source voltage \( v_s \). ### Diagram Explanation: 1. **Voltage Source (\( v_s \))**: - Denoted by a circle with a positive and negative sign, indicating the input voltage to the amplifier circuit. 2. **Operational Amplifier**: - Depicted by a triangle with a positive (+) and negative (-) input terminal. - **Inverting Input (-)**: The line connecting this terminal is linked to the node between \( R_1 \) and \( R_2 \). - **Non-inverting Input (+)**: This terminal is connected to the voltage source \( v_s \). 3. **Resistors**: - **\( R_1 \)**: Connected between the inverting input and ground. - **\( R_2 \)**: Connected between the inverting input and the output of the operational amplifier. 4. **Output Voltage (\( v_o \))**: - Represented at the output terminal of the operational amplifier. - The voltage \( v_o \) is directed towards terminals \( a \) and \( b \), with \( a \) being positive and \( b \) being negative. ### Target Equation: - The output voltage equation describes the relationship: \( v_o = - \left( \frac{R_2}{R_1} \right) v_s \). - To achieve \( v_o = 7.5v_s \), the resistances \( R_1 \) and \( R_2 \) must be selected such that \( \frac{R_2}{R_1} = 7.5 \).
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