Select Function 2, f(x) = Vx, under the Explore & Test section of the Explore It. (a) According to the e-8 definition of the limit, if lim Vx = 2 and ɛ = 0.9, there is a value of 8 for which |x – 4| < 8 implies lVx - 2| < e. What is the maximum X→4 value of 8, for which this is true? 8 = (b) Would this value also work for 8,? Yes No If not, what is the maximum value of 8, for which 4 – x < 8, would ensure |Vx – 2| < ɛ? (If it does work, enter the value in the blank below.) 1 81 = (c) What value of 8 should you choose in order for |Vx - 2| < e whenever |x – 4| < 8? 8 = %3D
Select Function 2, f(x) = Vx, under the Explore & Test section of the Explore It. (a) According to the e-8 definition of the limit, if lim Vx = 2 and ɛ = 0.9, there is a value of 8 for which |x – 4| < 8 implies lVx - 2| < e. What is the maximum X→4 value of 8, for which this is true? 8 = (b) Would this value also work for 8,? Yes No If not, what is the maximum value of 8, for which 4 – x < 8, would ensure |Vx – 2| < ɛ? (If it does work, enter the value in the blank below.) 1 81 = (c) What value of 8 should you choose in order for |Vx - 2| < e whenever |x – 4| < 8? 8 = %3D
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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
Transcribed Image Text:Select Function 2, f(x) = Vx, under the Explore & Test section of the Explore It.
(a) According to the e-8 definition of the limit, if lim Vx = 2 and ɛ = 0.9, there is a value of 8 for which |x – 4| < 8 implies lVx - 2| < e. What is the maximum
X→4
value of 8, for which this is true?
8 =
(b) Would this value also work for 8,?
Yes
No
If not, what is the maximum value of 8, for which 4 – x < 8, would ensure |Vx – 2| < ɛ? (If it does work, enter the value in the blank below.)
1
81 =
(c) What value of 8 should you choose in order for |Vx - 2| < e whenever |x – 4| < 8?
8 =
%3D
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