Let f(x) = 3x7 if x < 5 if 755 x ≥ 5 Show that f(x) has a jump discontinuity at x = 5 by calculating the limits from the left and right at x = 5. lim f(x) = 8 x-5- lim f(x) = -30 X
Let f(x) = 3x7 if x < 5 if 755 x ≥ 5 Show that f(x) has a jump discontinuity at x = 5 by calculating the limits from the left and right at x = 5. lim f(x) = 8 x-5- lim f(x) = -30 X
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![**Piecewise Function Analysis and Discontinuity**
Consider the piecewise function \( f(x) \):
\[
f(x) =
\begin{cases}
3x - 7 & \text{if } x < 5 \\
\frac{5}{x+5} & \text{if } x \geq 5
\end{cases}
\]
To demonstrate that \( f(x) \) has a jump discontinuity at \( x = 5 \), we calculate the limits from the left and right at this point.
1. **Left-hand Limit:**
\(\lim_{x \to 5^-} f(x)\)
Evaluating using \(3x - 7\):
\[
= 3(5) - 7 = 15 - 7 = 8
\]
*Result:* \( \lim_{x \to 5^-} f(x) = 8 \) (Correct)
2. **Right-hand Limit:**
\(\lim_{x \to 5^+} f(x)\)
Evaluating using \(\frac{5}{x+5}\):
\[
= \frac{5}{5+5} = \frac{5}{10} = 0.5
\]
Note: The image incorrectly shows \(-30\) as the value, which is a mistake.
The discrepancy between the left-hand limit and right-hand limit at \( x = 5 \) illustrates a jump discontinuity, confirming that \( f(x) \) is not continuous at this point.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F79384b4f-f6f5-4976-8d61-12e63a60eeb0%2Fa2857985-8ab7-47c3-8c30-1f1ea0cea3be%2F2b874qn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Piecewise Function Analysis and Discontinuity**
Consider the piecewise function \( f(x) \):
\[
f(x) =
\begin{cases}
3x - 7 & \text{if } x < 5 \\
\frac{5}{x+5} & \text{if } x \geq 5
\end{cases}
\]
To demonstrate that \( f(x) \) has a jump discontinuity at \( x = 5 \), we calculate the limits from the left and right at this point.
1. **Left-hand Limit:**
\(\lim_{x \to 5^-} f(x)\)
Evaluating using \(3x - 7\):
\[
= 3(5) - 7 = 15 - 7 = 8
\]
*Result:* \( \lim_{x \to 5^-} f(x) = 8 \) (Correct)
2. **Right-hand Limit:**
\(\lim_{x \to 5^+} f(x)\)
Evaluating using \(\frac{5}{x+5}\):
\[
= \frac{5}{5+5} = \frac{5}{10} = 0.5
\]
Note: The image incorrectly shows \(-30\) as the value, which is a mistake.
The discrepancy between the left-hand limit and right-hand limit at \( x = 5 \) illustrates a jump discontinuity, confirming that \( f(x) \) is not continuous at this point.
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