Select a standard rolled steel I-section for the simply supported beam of length 8 m and carries a UDLof w= 10kN/m shown in Figure 3. A factor of safety of 5 is to apply and the ultimate tensile strength ofthe material is 400 MPa. The selected section must have the least possible weight. The weight of thebeam itself may be neglected when calculating the maximum bending moment.Figure 3

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Answered: Select a standard rolled steel…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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A cantilever beam made of Aluminum alloy of circular cross-section as shown in the figure below is subjected to a load which varies from -F to +2F. The length of the beam is 115 mm and it has a diameter of 11 mm. Determine the maximum load that the given beam material can withstand for an indefinite life with a factor of safety 1.5. The fatigue stress concentration factor is 1.36. Assume the following values: Yield strength = 425 MN/mm2, endurance stress =254 MN/mm2, ultimate strength = 576 MN/mm2, size factor = 0.82, surface finish factor = 0.87. Use Goodman relation in your design. Also calculate the variable stress in N/mm2.
b) The beam shown in Figure Q3 (b) and (c) is made of steel with Young's Modulus of 200GPA and Yield Stress of 250MPA. The length L is 4m and the beam is pinned at A and supported by a roller at B. Calculate the Elastic-Plastic Moment for the cross-section shown in Figure Q3 (c) if the depth of plastic zone is 4mm. i. ii. Determine the value of distributed load w shown in Figure Q3 (b) if the length of the yielded zone is 50mm. t b A B h L Figure Q3 (c) Figure Q3 (b) Front view of simply supported beam Cross-section of beam b = 100mm, h = 40mm t = 4mm
Picture given below; There is a uniformly distributed load on the beam, which is made of Al2010 (T4) alloy T-profile and is connected to the "A" sliding bearing with "B" joint fixed support. Safe compression and tensile normal stress of the beam is Gemn=100 MPa. q=23 kN/m C-C Kesiti + 15 | 18 | 15 q=23 kN/m A유 30 cm 100 cm 150 cm 16 KİRİŞ T- PROFİLİ 74 Ød MAFSAL PİMİ Ölçüler mm dir. 104 S-1) Calculate the support reactions by drawing the SCD of the beam. S-2) The beam; a) Draw the shear force diagram, b) Moment diagram and determine the maximum moment. S-3) Find the x and y axis coordinates of the center of gravity of the cross-sectional area of the beam whose T-profile dimensions are given. S-4) Find the moments of inertia with respect to the vertical and horizontal axes passing through the center of gravity of the T-profile cross-section area. S-5) Find the tensile and compression stresses caused by bending on the beam with T-profile and check the safe carrying condition of this…
A simply supported beam is subjected to a distributed load of wi=640 N/m and a point load pi = 940 N. Calculate the internal loadings on the cross section at C. %3D D 1. 3. 6. The internal normal load at C is N = 1280 X N. The internal shear load at C is V = 242 XN. The internal bending moment at C is M = 476 o N-m.
A WT305 x 41 standard steel shape is used to support the loads shown. Assume w = 46 kN/m, LaB = 1.2 m, LBC = 2.4 m, and LcD = 1.2 m. Consider the entire 4.8 m length of the beam and determine: (a) the maximum tensile bending stress at any location along the beam (enter a positive answer), and (b) the maximum compressive bending stress at any location along the beam (enter a negative answer). %3D B LAB LBC LCD WT305 x 41 Answer: (а) Omax,T MPa (b) Omax,C = MPа %3D
Required Ihmai -- Q4/ A curved beam of a round cross section is shown in figure 3. The beam is made of a plain carbon steel 3OC8 (oy = 400 N/mm2) and the factor of safety is 3.5. Determine the dimensions of the beam Q4/* kN R= 4D Figure 3 ×ト kN O D= 21.53 mm D = 19.03 mm O D= 20.10 mm 23.30 m
4
In figure 1, a curved beam has a solid circular cross-section of 0.10 m in diameter. If a maximum tensile and compressive stress in the member are not to exceed 150 MPa and 200 MPa, respectively, determine the value of the load P that can safely be carried by the member. 1 D = 0.10 m 2 0.15 m 0.05 m R=0.10 m P
The beam shown below is made of air-dried Douglas fir (E = 1900 ksi) with an allow- able flexural stress of 2000 psi, an allowable shearing stress of 85 psi, and an allowable deflection of 0.8 in. Select the lightest standard structural timber that can be used to support the load shown in the figure. 12 ft 8000 lb B 12 ft C

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