Şekilde gösterildiği gibi sıcaklık 24°C iken 0,5 mm'lik boşluk bırakılmıştır. Alüminyum çubuktaki normal gerilme 75 MPa olması için gerekli sıcaklığın yaklaşık değerini (°C) olarak belirleyiniz. 0.5 mm 350 ) mm 450 mm Al 70 AB=1500 mm2 AAI=1800 mm² 74 EB=105 GPa EAI=73 GPa 90 aB=21,6.10-6 1/°C, aAI =23,2.10-6 1/°C 94 Formüller: 68 F.L AL = a.L.AT, AL = A.E F σ= Ε.ε, ε-

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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As shown in the figure, when the temperature was 24 ° C, a 0.5 mm gap was left. Determine the approximate value (° C) of the required temperature so that the normal stress in the aluminum bar is 75 MPa.

Şekilde gösterildiği gibi sıcaklık 24°C iken
0,5 mm'lik boşluk bırakılmıştır. Alüminyum
çubuktaki normal gerilme 75 MPa olması
için gerekli sıcaklığın yaklaşık değerini
0.5 mm
350 mm
450 mm
Al
B
(°C) olarak belirleyiniz.
70
AB=1500 mm2
AAI=1800 mm2
74
EB=105 GPa
EAI=73 GPa
90
aB=21,6.10-6 1/°C, aai =23,2.10-6 1/°C
94
Formüller:
68
F.L
ΔL α.L.ΔΤ, ΔL-
A.E
F
O =
A
σ= Ε.ε, ε-
Transcribed Image Text:Şekilde gösterildiği gibi sıcaklık 24°C iken 0,5 mm'lik boşluk bırakılmıştır. Alüminyum çubuktaki normal gerilme 75 MPa olması için gerekli sıcaklığın yaklaşık değerini 0.5 mm 350 mm 450 mm Al B (°C) olarak belirleyiniz. 70 AB=1500 mm2 AAI=1800 mm2 74 EB=105 GPa EAI=73 GPa 90 aB=21,6.10-6 1/°C, aai =23,2.10-6 1/°C 94 Formüller: 68 F.L ΔL α.L.ΔΤ, ΔL- A.E F O = A σ= Ε.ε, ε-
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