Segment AB is tangent to OTat B. What is the radius of OT? A 25 C. 45 B O A. 20 о в. 25 O C. 28 O D. 10/14 ト

Elementary Geometry For College Students, 7e
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ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
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Question 24

 

### Tangent to Circle Geometry Problem

**Problem Description:**

In the given diagram, segment \( AB \) is tangent to the circle \( T \) at point \( B \). The goal is to determine the radius of circle \( T \).

**Diagram Explanation:**

- There is a circle labeled \( T \) with a tangent line at point \( B \).
- Point \( A \) is outside the circle, forming triangle \( ABT \) with known segments \( AC \) and \( AC \).

Key details:
- \(\angle ACB = 90^\circ\)
- \( AC = 25 \)
- \( AB = 45 \)

**Question:**

What is the radius \( r \) of circle \( T \)?

**Answer Choices:**

- A. \( 20 \)
- B. \( 25 \)
- C. \( 28 \)
- D. \( 10\sqrt{14} \)

Using the Pythagorean theorem, solve for the radius \( r \).

### Detailed Solution:

1. Recognize that \( \angle ACB \) is a right angle since segment \( AB \) is tangent to \( T \) at \( B \).
2. Therefore, \( \Delta ACB \) is a right triangle with hypotenuse \( AB \).

Applying the Pythagorean theorem:
\[ AB^2 = AC^2 + BC^2 \]

Given:
\[ AB = 25 \]
\[ AC = 45 \]
Substitute into the Pythagorean theorem:
\[ 45^2 = 25^2 + r^2 \]

Solve for \( r \):
\[ 2025 = 625 + r^2 \]
\[ 1400 = r^2 \]
\[ r = \sqrt{1400} \]
\[ r = 10 \sqrt{14} \]

**Correct Option:**
D. \( 10 \sqrt{14} \)
Transcribed Image Text:### Tangent to Circle Geometry Problem **Problem Description:** In the given diagram, segment \( AB \) is tangent to the circle \( T \) at point \( B \). The goal is to determine the radius of circle \( T \). **Diagram Explanation:** - There is a circle labeled \( T \) with a tangent line at point \( B \). - Point \( A \) is outside the circle, forming triangle \( ABT \) with known segments \( AC \) and \( AC \). Key details: - \(\angle ACB = 90^\circ\) - \( AC = 25 \) - \( AB = 45 \) **Question:** What is the radius \( r \) of circle \( T \)? **Answer Choices:** - A. \( 20 \) - B. \( 25 \) - C. \( 28 \) - D. \( 10\sqrt{14} \) Using the Pythagorean theorem, solve for the radius \( r \). ### Detailed Solution: 1. Recognize that \( \angle ACB \) is a right angle since segment \( AB \) is tangent to \( T \) at \( B \). 2. Therefore, \( \Delta ACB \) is a right triangle with hypotenuse \( AB \). Applying the Pythagorean theorem: \[ AB^2 = AC^2 + BC^2 \] Given: \[ AB = 25 \] \[ AC = 45 \] Substitute into the Pythagorean theorem: \[ 45^2 = 25^2 + r^2 \] Solve for \( r \): \[ 2025 = 625 + r^2 \] \[ 1400 = r^2 \] \[ r = \sqrt{1400} \] \[ r = 10 \sqrt{14} \] **Correct Option:** D. \( 10 \sqrt{14} \)
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