sec 4.7: Problem 4 Solve the partial differential equation problem = Utt 4Uxx 0 < x <1, t>0 u(0,t) = u(1,t) = 0 Boundary conditions: Initial conditions: u(x, 0) = 8 sin(2πx), u(x,t) = ☐ help (formulas) Book: Section 4.7 of Notes on Diffy Qs ut(x, 0) 5 sin(3πx) =

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A: Note: General solution= Complementary function (C.F.) + Particular integral (P.I.)

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A: The five points of the first cycle are:(−0.42403, 0),(−1.14677, 0),(0, −3),(4π​, −7)and(−4π​, 1)

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