Consider the following initial value problem, defined for t > 0: x' - 2x = t (t - w) e²w dw, 2w x(0) = = −1. Find the Laplace transform of the solution. X(s) = L {x(t)} = 1-83+22 1s 2s s²(5-2)² Obtain the solution x(t). x(t) = help (formulas) help (formulas)
Consider the following initial value problem, defined for t > 0: x' - 2x = t (t - w) e²w dw, 2w x(0) = = −1. Find the Laplace transform of the solution. X(s) = L {x(t)} = 1-83+22 1s 2s s²(5-2)² Obtain the solution x(t). x(t) = help (formulas) help (formulas)
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 18T
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![Consider the following initial value problem, defined for t > 0:
x' - 2x
=
t
(t - w) e²w dw,
2w
x(0) =
= −1.
Find the Laplace transform of the solution.
X(s) = L {x(t)} =
1-83+22
1s 2s
s²(5-2)²
Obtain the solution x(t).
x(t)
=
help (formulas)
help (formulas)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4fe2b77a-506d-44bb-8c9b-0ebb3bef939b%2F73ed6355-9c57-4fbf-a556-50fd5bd278d1%2Fdzw82vj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Consider the following initial value problem, defined for t > 0:
x' - 2x
=
t
(t - w) e²w dw,
2w
x(0) =
= −1.
Find the Laplace transform of the solution.
X(s) = L {x(t)} =
1-83+22
1s 2s
s²(5-2)²
Obtain the solution x(t).
x(t)
=
help (formulas)
help (formulas)
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