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sec 4.10: Problem 4 Using the Poisson integral solve the Dirichlet problem in the circle of radius 1 using polar coordinates: V²U = Upp + 1¼ Up + 1 = 0 for 0 < r < 1. u(1,0) = if 0 < < π else u(r, 0): = 1 2πT РП S da help (formulas) 0 Note: Use "theta" for 0 and "alpha" for a, the variable of integration. Now solve V²W = Wrp + ¼ Wr + woo = 0 for 0 < r <1. w(1, 0) = 0², 1 πT < w(1, 0) = ☐ da help (formulas) 2πT -πT Note: Use "theta" for 0 and "alpha" for a, the variable of integration.

sec 4.10: Problem 4 Using the Poisson integral solve the Dirichlet problem in the circle of radius 1 using polar coordinates: V²U = Upp + 1¼ Up + 1 = 0 for 0 < r < 1. u(1,0) = if 0 < < π else u(r, 0): = 1 2πT РП S da help (formulas) 0 Note: Use "theta" for 0 and "alpha" for a, the variable of integration. Now solve V²W = Wrp + ¼ Wr + woo = 0 for 0 < r <1. w(1, 0) = 0², 1 πT < w(1, 0) = ☐ da help (formulas) 2πT -πT Note: Use "theta" for 0 and "alpha" for a, the variable of integration.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter7: Analytic Trigonometry
Section7.6: The Inverse Trigonometric Functions
Problem 37E
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sec 4.10: Problem 4 Using the Poisson integral solve the Dirichlet problem in the circle of radius 1 using polar coordinates: V²U = Upp + 1¼ Up + 1 = 0 for 0 < r < 1. u(1,0) = if 0 < < π else u(r, 0): = 1 2πT РП S da help (formulas) 0 Note: Use "theta" for 0 and "alpha" for a, the variable of integration. Now solve V²W = Wrp + ¼ Wr + woo = 0 for 0 < r <1. w(1, 0) = 0², 1 πT < w(1, 0) = ☐ da help (formulas) 2πT -πT Note: Use "theta" for 0 and "alpha" for a, the variable of integration.
Transcribed Image Text:sec 4.10: Problem 4 Using the Poisson integral solve the Dirichlet problem in the circle of radius 1 using polar coordinates: V²U = Upp + 1¼ Up + 1 = 0 for 0 < r < 1. u(1,0) = if 0 < < π else u(r, 0): = 1 2πT РП S da help (formulas) 0 Note: Use "theta" for 0 and "alpha" for a, the variable of integration. Now solve V²W = Wrp + ¼ Wr + woo = 0 for 0 < r <1. w(1, 0) = 0², 1 πT < w(1, 0) = ☐ da help (formulas) 2πT -πT Note: Use "theta" for 0 and "alpha" for a, the variable of integration.
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