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- Find a system of two equations in three variables, x1, x2 and x3 that has the solution set given by the parametric representation x1=t, x2=s and x3=3+st, where s and t are any real numbers. Then show that the solutions to the system can also be written as x1=3+st,x2=s and x3=t.Determine whether T is linear , if not state whether it is the additivity or the homogenity property (or both ) that fails . T(x,y,z) =(0,0) T(x,y,z) =(y^2 ,z) T(x,y,z) =(3x-4y, 2x-5z5c) Find the partial derivatives? y = 2x2+3xz+85w-8z2
- I) Compute the matrix of partial derivatives of the following functions: @) f: R² → IR², fcx,y) = (x,y) b.) f: (R² R³₁ fcx,y) = (xe ² + cosy, x₁ x + (²) C.) f:IR ²³ - IR²₁ fcx,y, z) = (x+e² +y₁ yx²) ту, d.) f: IR² R³, f(x,y) = (xyexy, xsiny, 5 xy²) PCY (0,0) to laterfil danidentify the equilibrium points, calculate the Jacobian, and explain what the linearization theorem tells us about the stability of each equilbrium pointFind the extreme values
- Solve using Lagrange Multipliers and show how to get the partial derivatives.If the partial derivatives of A, B. U, and Vare assumed to exist, then I. V(U + V) = VU + VV or grad (U+ )3grad u+ grad V 2. V (A +B) = V-A+V B or div (A + B) +div A + div B 3. Vx (A +B) = VxA+VxB or curl (A + B) = curlA+ curl B 4. V.(UA) = (VU) - A+ U(V A) 5. Vx (UA) = (VU) xA + U(V x A) 6. V.(A x B) = B (Vx A)-A (Vx B) 7. Vx (A x B) = (B V)A- B(V A)-(A V)B+ A(V B) 8. V(A B) (B V)A+ (A V)B+ Bx (Vx A) + A x (V x B) 9. V.(VU) = VU= is called the Laplacian of U. +. and V =. ar dyaz is called the Lapacian operator. 10. Vx (VU) =0. The curl of the gradient of U is zero, 11. V.(Vx A) = 0. The divergence of the curl of A is zero. 12. Vx (Vx A)= V(V. A)-V AThe curve crosses the x axis at A(2, 0) and at the point B(10, 0). The curve has a minimum at M(3, −6). YA H A(2,0) M (3,-6) y = f(x) B (10,0) X a) Write down the co-ordinate of A, B and M under the tranformation y = f(2x). A= ( ), B = ( ), M = ( b) Write down the co-ordinates of the A, B and M under the transformation y = -2f(x) + 3. A = ( " ), B = ( " ), M=( " ) )