Scheduled maintenance will close two of the four westbound lanes of a freeway during one weekday for the period from 9:00 AM to 4:00 PM. The demand on the two lanes are as follows: Time Demand, vph 9:00-10:00 АМ 4000 10:00-11:00 AM 3500 11:00-12:00 NN 2500 12:00-1:00 PM 2000 1:00-2:00 PM 2000 2:00-3:00 PM 2000 B:00-4:00 PM 2000 If the estimated capacity of the 4 lanes with 2 lanes open is 2960 vph, a. compute the time when maximum queue occurs. 11:00 AM p. compute the maximum queue formed. 1580 vehicles :. compute the maximum length of queue if the average length of cars is equal to 5 meters. 1975 m Show all necessary diagrams and solutions.

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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Scheduled maintenance will close two of the four westbound lanes of a freeway during one weekday for the period from 9:00 AM to 4:00 PM. The demand on the two lanes are as follows:
Time Demand, vph
9:00-10:00 AM 4000
10:00-11:00 AM 3500
11:00-12:00 NN 2500
12:00-1:00 PM 2000
1:00-2:00 PM 2000
2:00-3:00 PM 2000
3:00-4:00 PM 2000
If the estimated capacity of the 4 lanes with 2 lanes open is 2960 vph,
a. compute the time when maximum queue occurs. 11:00 AM
b. compute the maximum queue formed. 1580 vehicles
c. compute the maximum length of queue if the average length of cars is equal to 5 meters. 1975 m
Show all necessary diagrams and solutions.
Transcribed Image Text:Scheduled maintenance will close two of the four westbound lanes of a freeway during one weekday for the period from 9:00 AM to 4:00 PM. The demand on the two lanes are as follows: Time Demand, vph 9:00-10:00 AM 4000 10:00-11:00 AM 3500 11:00-12:00 NN 2500 12:00-1:00 PM 2000 1:00-2:00 PM 2000 2:00-3:00 PM 2000 3:00-4:00 PM 2000 If the estimated capacity of the 4 lanes with 2 lanes open is 2960 vph, a. compute the time when maximum queue occurs. 11:00 AM b. compute the maximum queue formed. 1580 vehicles c. compute the maximum length of queue if the average length of cars is equal to 5 meters. 1975 m Show all necessary diagrams and solutions.
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