Scenario: Terry Teacher suspects that kindergarten class sizes in Alameda county are larger thanaverage. According to the California Department of Education, the average kindergarten class size inCalifornia is 21.9. For a random sample of 36 Alameda County kindergarten classes, the averageclass size was 23 with a standard deviation of two. Run a test to assess Terry Teacher's hypothesis atthe a=.05 level.Question: Given the p-value you calculated, which of the following is a correct conclusion for thistest? (select all that apply)There is no support for the alternative hypothesisBecause p < , we can reject the null hypothesisBecause p > a , we fail to reject the null hypothesisThere is support for the alternative hypothesis

Answered: Image /qna-images/answer/fdf7f128-4541-4567-ac08-a10cb0b1d744.jpg

Answered: Scenario: Terry Teacher suspects that…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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An electrician wants to know whether batteries made by two manufacturers have significantly different voltages. The voltage of 58 batteries from each manufacturer were measured. The population standard deviations of the voltage for each manufacturer are known. The results are summarized in the following table. Manufacturer Sample mean voltage (millivolts) Population standard deviation(millivolts) A 186 2 B 185 3 What type of hypothesis test should be performed? What is the test statistic? Does sufficient evidence exist to support the claim that the voltage of the batteries made by the two manufacturers is different at the α=0.1 significance level?yes or no
A shoe manager claims that the average cost of a pier of tennis shoes is $89.95. A sample of 68 pairs of tennis shoes has a average code of $90.26. The standard deviation is $3. What is the test statistic if we were to claim at a=0.05?
Ideal Number of Children Frequency 0. 11 27 528 262 63 10 4. 8. 6. 0. 10 11 H23456
The mean number of eggs per person eaten in the United States is 244. Do college students eat a different number of eggs than the average American? The 60 college students surveyed averaged 255 eggs per person and their standard deviation was 64.4. What can be concluded at the a = 0.10 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: Ho: ? v Select an answer v Н: Select an answer V c. The test statistic ? v = (please show your answer to 3 decimal places.) d. The p-value (Please show your answer to 4 decimal places.) e. The p-value is ? va f. Based on this, we should Select an answer g. Thus, the final conclusion is that ... the null hypothesis. O The data suggest that the populaton mean is significantly different from 244 at a = 0.10, so there is statistically significant evidence to conclude that the population mean number of eggs consumed by college students per year is different from 244. O The data suggest…
University of Florida football programs are printed 1 week prior to each home game. Attendance averages 75,000 screaming and loyal Gators fans, of whom two-thirds usually buy the program, following a normal distribution, for $5 each. Unsold programs are sent to a recycling center that pays only 10 cents per program. The standard deviation is 10,000 programs, and the cost to print each program is $1. Refer to the standard normal table for z-values. a) What is the cost of underestimating demand for each program? Cs = $ (round your response to two decimal places).
Which of the following is the correct p-value for this test?
Can you help me determine the P-value for the following hypothesis test?
An auditor, pressed for time and on a low budget, is concerned with account errors on customer credit. She takes a sample of 25 accounts, and finds the account error, on average, is $-23, with a standard deviation of $16. Is the claim of the manager that errors average only $-10 supported? In this case, the null hypothesis is what?
A magazine article claims that the average cost for a take-out lunch is $9.22. You randomly select a sample of 38 take-out restaurants, and look up the price of their most popular lunch combo. You find an average of $10.08. Assume a population standard deviation of $2.13. a. State the null and alternative hypothesis for the claim that the average cost for a take-out lunch is $9.22. Ho: ? ______9.22 Ha: ? ______ 9.22 b. The _______ hypothesis is the claim. c. The goal of the test is to _______ the claim.
You are a manager of a building that hosts the local farmers market for a town. You want to investigate if the average amount of sales for a vendor per week at your building is greater than $2040. After surveying 17 of their vendors, you find that mean sales per week of the vendors sampled was $2110 with a standard deviation of $114.03. What is the value of the test statistic for your hypothesis test? Note: 1- Only round your final answer. Round your final answer to two decimal places.
In a particular city, the average annual salary for secretaries is $28,000. A sample of 50 secretaries from Company A shows an average annual salary of $24,500 with a population standard deviation of $4500. Secretaries at Company A claim they are paid less than the city average. What is the test value for this claim?
Sales at a fast-food restaurant average $6,000 per day. The restaurant decided to introduce an advertising campaign to increase daily sales. To determine the effectiveness of the advertising campaign, a sample of 49 days of sales were taken. They found that the average daily sales were $6,300 per day. From past history, the restaurant knew that its population standard deviation is about $1,000. The restaurant wishes to test whether sales have increased as a result of the advertising campaign. If the level of significance is 0.05, what is the decision? Multiple Choice Fail to reject the null hypothesis. Reject the null hypothesis and conclude the mean is higher than $6,000 per day. Reject the null hypothesis and conclude the mean is lower than $6,000 per day. Reject the null hypothesis and conclude that the mean is equal to $6,000 per day.

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