College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![### Physics Problem: Moment of Inertia
Sarah has a hollow ball that rolls across the room. If it has a diameter of 4.00 meters and a mass of 3000 grams, find its moment of inertia.
#### Answer Choices:
- 6 kg m²
- 48 kg m²
- 8 kg m²
- 4.8 kg m²
- 12 kg m²
#### Explanation:
To solve this problem, use the formula for the moment of inertia of a hollow sphere:
\[ I = \frac{2}{3} M R^2 \]
where \( M \) is the mass and \( R \) is the radius.
Given:
- Diameter of the ball \( d = 4.00 \) meters
- Radius \( R = \frac{d}{2} = 2.00 \) meters
- Mass \( M = 3000 \) grams = 3 kg
Substitute the given values into the formula:
\[ I = \frac{2}{3} \times 3 \, \text{kg} \times (2.00 \, \text{m})^2 \]
\[ I = \frac{2}{3} \times 3 \, \text{kg} \times 4.00 \, \text{m}^2 \]
\[ I = \frac{2}{3} \times 12 \, \text{kg} \cdot \text{m}^2 \]
\[ I = 8 \, \text{kg} \cdot \text{m}^2 \]
Therefore, the correct answer is **8 kg m²**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8afc82ac-131b-4872-93f6-baa956562cd6%2F583d6247-cb47-4755-b3f7-b41995c79de8%2F0syxgx_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Physics Problem: Moment of Inertia
Sarah has a hollow ball that rolls across the room. If it has a diameter of 4.00 meters and a mass of 3000 grams, find its moment of inertia.
#### Answer Choices:
- 6 kg m²
- 48 kg m²
- 8 kg m²
- 4.8 kg m²
- 12 kg m²
#### Explanation:
To solve this problem, use the formula for the moment of inertia of a hollow sphere:
\[ I = \frac{2}{3} M R^2 \]
where \( M \) is the mass and \( R \) is the radius.
Given:
- Diameter of the ball \( d = 4.00 \) meters
- Radius \( R = \frac{d}{2} = 2.00 \) meters
- Mass \( M = 3000 \) grams = 3 kg
Substitute the given values into the formula:
\[ I = \frac{2}{3} \times 3 \, \text{kg} \times (2.00 \, \text{m})^2 \]
\[ I = \frac{2}{3} \times 3 \, \text{kg} \times 4.00 \, \text{m}^2 \]
\[ I = \frac{2}{3} \times 12 \, \text{kg} \cdot \text{m}^2 \]
\[ I = 8 \, \text{kg} \cdot \text{m}^2 \]
Therefore, the correct answer is **8 kg m²**.
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