Sarah has a hollow ball that rolls across the room. If it has a diameter of 4.00 m and a mass of 3000 grams, find its' moment of inertia?

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### Physics Problem: Moment of Inertia

Sarah has a hollow ball that rolls across the room. If it has a diameter of 4.00 meters and a mass of 3000 grams, find its moment of inertia.

#### Answer Choices:
- 6 kg m²
- 48 kg m²
- 8 kg m²
- 4.8 kg m²
- 12 kg m²

#### Explanation:
To solve this problem, use the formula for the moment of inertia of a hollow sphere:

\[ I = \frac{2}{3} M R^2 \]

where \( M \) is the mass and \( R \) is the radius.

Given:
- Diameter of the ball \( d = 4.00 \) meters
- Radius \( R = \frac{d}{2} = 2.00 \) meters
- Mass \( M = 3000 \) grams = 3 kg

Substitute the given values into the formula:

\[ I = \frac{2}{3} \times 3 \, \text{kg} \times (2.00 \, \text{m})^2 \]

\[ I =  \frac{2}{3} \times 3 \, \text{kg} \times 4.00 \, \text{m}^2 \]

\[ I =  \frac{2}{3} \times 12 \, \text{kg} \cdot \text{m}^2 \]

\[ I =  8 \, \text{kg} \cdot \text{m}^2 \]

Therefore, the correct answer is **8 kg m²**.
Transcribed Image Text:### Physics Problem: Moment of Inertia Sarah has a hollow ball that rolls across the room. If it has a diameter of 4.00 meters and a mass of 3000 grams, find its moment of inertia. #### Answer Choices: - 6 kg m² - 48 kg m² - 8 kg m² - 4.8 kg m² - 12 kg m² #### Explanation: To solve this problem, use the formula for the moment of inertia of a hollow sphere: \[ I = \frac{2}{3} M R^2 \] where \( M \) is the mass and \( R \) is the radius. Given: - Diameter of the ball \( d = 4.00 \) meters - Radius \( R = \frac{d}{2} = 2.00 \) meters - Mass \( M = 3000 \) grams = 3 kg Substitute the given values into the formula: \[ I = \frac{2}{3} \times 3 \, \text{kg} \times (2.00 \, \text{m})^2 \] \[ I = \frac{2}{3} \times 3 \, \text{kg} \times 4.00 \, \text{m}^2 \] \[ I = \frac{2}{3} \times 12 \, \text{kg} \cdot \text{m}^2 \] \[ I = 8 \, \text{kg} \cdot \text{m}^2 \] Therefore, the correct answer is **8 kg m²**.
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