Sand moves without slipping at 6.0 m/sm/s down a conveyer that is tilted at 15∘∘. The sand enters a pipe hhh = 5.0 mm below the end of the conveyer belt, as shown in the figure (Figure 1). **Educational Exercise: Analyzing the Motion of Sand on a Conveyor Belt**---### Problem StatementSand moves without slipping at a velocity of 6.0 m/s down a conveyor belt that is tilted at an angle of 15°. The sand enters a pipe located 5.0 meters below the end of the conveyor belt, as depicted in the accompanying diagram (Figure 1).---### Objective**Part A:**Calculate the horizontal distance \( d \) between the end of the conveyor belt and the entry point of the pipe.*Express your answer to two significant figures and include the appropriate units.*\[ d = \_\_\_\_\_\_\_\_ \text{Units} \]**Action: Submit your answer using the provided format.**---### Diagram ExplanationThe diagram illustrates a side view of the conveyor belt setup:- The conveyor belt is inclined at 15°.- Sand moves at a speed of 6 m/s along the belt.- The sand then follows a trajectory to enter a pipe that is vertically 5 meters below the end of the conveyor belt.- Your task is to determine the horizontal distance, labeled \( d \), from the point where the sand leaves the conveyor to where it enters the pipe.Consider using principles of projectile motion to solve the problem, taking into account the angle of inclination and initial velocity.---**Feedback:** If you have any questions or need further clarification, feel free to reach out for assistance.

The equation of motion for projectile motion is given by Where x = Represents horizontal motion, y…

Answered: Sand moves without slipping at 6.0 m/s…