Sample pseudocode for the Task 2: for (each character ch in the infix expression) { switch (ch) { case operand: postfixExp = postfixExp ch break /I/ Append operand to end of postfix expression-step 1 // Save '(' on stack-step 2 case '(': operatorStack.push(ch) break case operator: I/ Process stack operators of greater precedence-step 3 while (!operatorStack.isEmpty() and operatorStack.peek() is not a '(' and precedence(ch) <= precedence(operatorStack.peek())) { Append operatorStack.peek()to the end of postfixExp operatorStack.pop(0 } operatorStack.push(ch) // Save the operator break // Pop stack until matching ('-step 4 case ')': while (operatorStack.peek() is not a '(') Append operatorStack.peek() to the end of postfixExp operatorStack.popO } operatorStack.pop0 / Remove the open parenthesis break // Append to postfixExp the operators remaining in the stack-step 5 while (!operatorStack.isEmpty()) { Append operatorStack.peek() to the end of postfixExp operatorStack.pop)

Sample pseudocode for the Task 2: for (each character ch in the infix expression) { switch (ch) { case operand: postfixExp = postfixExp ch break /I/ Append operand to end of postfix expression-step 1 // Save '(' on stack-step 2 case '(': operatorStack.push(ch) break case operator: I/ Process stack operators of greater precedence-step 3 while (!operatorStack.isEmpty() and operatorStack.peek() is not a '(' and precedence(ch) <= precedence(operatorStack.peek())) { Append operatorStack.peek()to the end of postfixExp operatorStack.pop(0 } operatorStack.push(ch) // Save the operator break // Pop stack until matching ('-step 4 case ')': while (operatorStack.peek() is not a '(') Append operatorStack.peek() to the end of postfixExp operatorStack.popO } operatorStack.pop0 / Remove the open parenthesis break // Append to postfixExp the operators remaining in the stack-step 5 while (!operatorStack.isEmpty()) { Append operatorStack.peek() to the end of postfixExp operatorStack.pop)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Question

Answer fast otherwise I’ll downvote/thumbs down it

Sample pseudocode for the Task 2:
for (each character ch in the infix expression)
{
switch (ch)
// Append operand to end of postfix expression-step 1
case operand:
postfixExp = postfixExp • ch
break
// Save '(' on stack-step 2
case '(':
operatorStack.push(ch)
break
case operator: // Process stack operators of greater precedence-step 3
while (!operatorStack.isEmpty() and operatorStack.peek() is not a '(' and precedence(ch)
<- precedence(operatorStack.peek()))
Append operatorStack.peek()to the end of postfixExp
operatorStack.popO
operatorStack.push(ch) // Save the operator
break
// Pop stack until matching '('–step 4
case '):
while (operatorStack.peek() is not a '().
{
Append operatorStack.peek() to the end of postfixExp
operatorStack.pop()
operatorStack.popO // Remove the open parenthesis
break
// Append to postfixExp the operators remaining in the stack-step 5
while (!operatorStack.isEmpty())
{
Append operatorStack.peek() to the end of postfixExp
operatorStack.popO
}

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