Sample pseudocode for the Task 2: for (each character ch in the infix expression) { switch (ch) { case operand: postfixExp = postfixExp ch break /I/ Append operand to end of postfix expression-step 1 // Save '(' on stack-step 2 case '(': operatorStack.push(ch) break case operator: I/ Process stack operators of greater precedence-step 3 while (!operatorStack.isEmpty() and operatorStack.peek() is not a '(' and precedence(ch) <= precedence(operatorStack.peek())) { Append operatorStack.peek()to the end of postfixExp operatorStack.pop(0 } operatorStack.push(ch) // Save the operator break // Pop stack until matching ('-step 4 case ')': while (operatorStack.peek() is not a '(') Append operatorStack.peek() to the end of postfixExp operatorStack.popO } operatorStack.pop0 / Remove the open parenthesis break // Append to postfixExp the operators remaining in the stack-step 5 while (!operatorStack.isEmpty()) { Append operatorStack.peek() to the end of postfixExp operatorStack.pop)

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Sample pseudocode for the Task 2:
for (each character ch in the infix expression)
{
switch (ch)
// Append operand to end of postfix expression-step 1
case operand:
postfixExp = postfixExp • ch
break
// Save '(' on stack-step 2
case '(':
operatorStack.push(ch)
break
case operator: // Process stack operators of greater precedence-step 3
while (!operatorStack.isEmpty() and operatorStack.peek() is not a '(' and precedence(ch)
<- precedence(operatorStack.peek()))
Append operatorStack.peek()to the end of postfixExp
operatorStack.popO
operatorStack.push(ch) // Save the operator
break
// Pop stack until matching '('–step 4
case '):
while (operatorStack.peek() is not a '().
{
Append operatorStack.peek() to the end of postfixExp
operatorStack.pop()
operatorStack.popO // Remove the open parenthesis
break
// Append to postfixExp the operators remaining in the stack-step 5
while (!operatorStack.isEmpty())
{
Append operatorStack.peek() to the end of postfixExp
operatorStack.popO
}
Transcribed Image Text:Sample pseudocode for the Task 2: for (each character ch in the infix expression) { switch (ch) // Append operand to end of postfix expression-step 1 case operand: postfixExp = postfixExp • ch break // Save '(' on stack-step 2 case '(': operatorStack.push(ch) break case operator: // Process stack operators of greater precedence-step 3 while (!operatorStack.isEmpty() and operatorStack.peek() is not a '(' and precedence(ch) <- precedence(operatorStack.peek())) Append operatorStack.peek()to the end of postfixExp operatorStack.popO operatorStack.push(ch) // Save the operator break // Pop stack until matching '('–step 4 case '): while (operatorStack.peek() is not a '(). { Append operatorStack.peek() to the end of postfixExp operatorStack.pop() operatorStack.popO // Remove the open parenthesis break // Append to postfixExp the operators remaining in the stack-step 5 while (!operatorStack.isEmpty()) { Append operatorStack.peek() to the end of postfixExp operatorStack.popO }
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