A sample of 36 observations is selected from a normal population. The sample mean is 49, and the population standard deviation is 5.Conduct the following test of hypothesis using the 0.05 significance level.He: H=50H₁: p 50a. Is this a one- or two-tailed test?O One-tailed testOTwo-tailed testb. What is the decision rule?CheckO Reject Ho if -1.96 < z < 1.96Reject He if z<-1.96 or z> 1.96 e-1. What is the p-value? (Round your z value to 2 decimal places and final answer to 4 decimal places.)p-valuee-2. Interpret the p-value? (Round your z value to 2 decimal places and final answer to 2 decimal places.)There is a% chance of finding a z value this large by sampling error when HQ is truec. What is the value of the test statistic? (Negative amount should be indicated by a minus sign. Round your answer to 2 decimalplaces.)Value of the test statistic

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Answered: sample of 36 observations is selected…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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One-Sample Z: Test of 35 vs not 35 %3D The assumed standard deviation 1.8 Variable N Мean StDev SE Mean 25 35.710 1.475 а. b. с. d. Is this a one-sided or a two-sided test? e. What would be the P-value if the alternative hypothesis is H1: µ > 35 v a. a. 0.00805 v b. b. 0.0243 v C. c. 2.4068 v d. d. 0.0486 е. 1.9722 е. f. Two-sided hypothesis test g. 0.295 h. One-sided test because alternative hypothesis, H : µ # 35 i. 0.360
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The average salary in this city is $43,200. Is the average more for single people? 47 randomly selected single people who were surveyed had an average salary of $49,485 and a standard deviation of $16,570. What can be concluded at the αα = 0.10 level of significance? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer ≠ < = > H1:H1: ? p μ Select an answer > ≠ = < The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? ≤ > αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis.
Moviegoers The average "moviegoer" sees 8.5 movies a year. A moviegoer is defined as a person who sees at least one movie in a theater in a 12-month period. A random sample of 42 moviegoers from a large university revealed that the average number of movies seen per person was 10.2. The population standard deviation is 3.2 movies. At the 0.01 level of significance, can it be concluded that this represents a difference from the national average? Part 1 of 5 State the hypotheses and identify the claim with the correct hypothesis. Hotu = 85 Part: 1/5 not claim H₁ 8.5 claim This hypothesis test is a two-tailed ▼test. Part 2 of 5 ▼ ▼ Find the critical value(s). Round the answer to at least two decimal places. If there is more than one critical value, separate them with commas. Critical value(s): X 0.0.... + 8分民图〗b. E
An electrician wants to know whether batteries made by two manufacturers have significantly different voltages. The voltage of 131 batteries from each manufacturer were measured. The population standard deviations of the voltage for each manufacturer are known. The results are summarized in the following table. Manufacturer Sample mean voltage (millivolts) Population standard deviat A 116 3 115 4 What type of hypothesis test should be performed? Right-tailed z-test v What is the test statistic? Ex: 0.12 Does sufficient evidence exist to support the claim that the voltage of the batteries made by the two manufacturers is different at the a = 0.01 significance level? Select v
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The average salary for American college graduates is $48,600. You suspect that the average is less for graduates from your college. The 49 randomly selected graduates from your college had an average salary of $46,486 and a standard deviation of $9,200. What can be concluded at the αα = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer = ≠ > < H1:H1: ? μ p Select an answer > ≠ = < The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that .
A banana company claims that the mean weight of their banana is 150 grams with a standard deviation of 18 grams. Data generated from a sample of 49 bananas randomly selected indicated a mean weight of 153.5 grams per banana. Is there sufficient evidence to reject the company's claim? Use a = 0.05. Population Standard Known/Unknown Hypothesis Test Number of z-value or Level of Hypotheses Decision Significance Sample t-value -30 -20 -1o 1o 20 30
IQ scores are normally distributed with a mean of 100 and a standard deviation of 15. A charter school wants to know if their students have an average IQ that is higher than the population average. They take a random sample of 25 students and find a mean IQ of 108 with a standard deviation of 21. Use a 5% significance level. What is the P value with work? Do we reject the null hypothesis in this case? What does the hypothesis test say about the mean pulse rate.
Claim: The mean systolic blood pressure of all healthy adults is less than than 120 mm Hg. Sample data: For 276 healthy adults, the mean systolic blood pressure level is 119.61 mm Hg and the standard deviation is 14.88 mm Hg. The null and alternative hypotheses are Ho: μ = 120 and H₁: μ< 120. Find the value of the test statistic. The value of the test statistic is (Round to two decimal places as needed.) C
Test the claim that the mean GPA of night students is significantly different than 2.6 at the 0.2 significance level. Based on a sample of 50 people, the sample mean GPA was 2.55 with a standard deviation of 0.04The test statistic is: ? (2 decimals)The p-value is: ? (2 decimals)

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