Same number of moles of Cu" and Zn" were dissolved into I Select two separate equimolar solutions of NH, K, of CulNHal" > K, of Zn!NHal" Consider carbonic acid. H;COy IH;CO,lag) - H;O) e-- HjO'laq) + HCO, taq) H,O'l from step | Select H3O"1 from step 2 1. HCO, tagl - H;O0 HO'lae). co, ue For two solutions of citric acid X ionization of I Select X ionization of pt of volution pH solution of solution Il solution

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Chapter1: Chemical Foundations
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I. Given the condition for each number, compare the quantities in Column I and Column II. From the drop down choice, answer:

greater than if the quantity in column I is greater than column II

less than if the quantity in column I is less than column II

equal to if the two quantities are equal

cannot be determined if the relationship cannot be determined from the given information

Same number of
moles of Cu" and
Zn" were dissolved
into
I Select
Za" n
two separate
equimolar solutions
of NH,
K, of CulNHl > K,
of Zn(NH
Consider carbonic
acid. H;CO;
I.H;CO,lag) - H;om
e--> HO'taq) +
HCO, taa)
H,O"l from step
| Select
[H,O"| from step 2
1. HCO, tag) - H;O)
HO'laa).
co, ue
For two solutions of
citric acid
K ionization of
solution i
X ionization of
I Select|
pH of solution pH solution
of solution i
Consider two
solutions
Solution E0.1M
HOO
POH of solution
I Select)
pOH of solution
Solution I: 01M
HCIO • 001 M
NaCIO
Transcribed Image Text:Same number of moles of Cu" and Zn" were dissolved into I Select Za" n two separate equimolar solutions of NH, K, of CulNHl > K, of Zn(NH Consider carbonic acid. H;CO; I.H;CO,lag) - H;om e--> HO'taq) + HCO, taa) H,O"l from step | Select [H,O"| from step 2 1. HCO, tag) - H;O) HO'laa). co, ue For two solutions of citric acid K ionization of solution i X ionization of I Select| pH of solution pH solution of solution i Consider two solutions Solution E0.1M HOO POH of solution I Select) pOH of solution Solution I: 01M HCIO • 001 M NaCIO
For two salts with
the same initial
concentration
Solution I: 0.10 M
Nax
pH of 0.10 M HX
( Select ]
pH of 0.10 M HY
Solution II: 0.10 M
NaY
pOH of solution I >
POH of solution II
Consider two
solutions
Solution I: 15 mL 0.2
M H3PO4 + 25 ml volume of 0.15 M
H20
volume of 0.15 M
-NAOH required to
neutralize solution
I Splect )
N2OH required to
neutralize solution I
Solution II: 10 mL 0.9
|М CH-COOH + 30
mL H20
Transcribed Image Text:For two salts with the same initial concentration Solution I: 0.10 M Nax pH of 0.10 M HX ( Select ] pH of 0.10 M HY Solution II: 0.10 M NaY pOH of solution I > POH of solution II Consider two solutions Solution I: 15 mL 0.2 M H3PO4 + 25 ml volume of 0.15 M H20 volume of 0.15 M -NAOH required to neutralize solution I Splect ) N2OH required to neutralize solution I Solution II: 10 mL 0.9 |М CH-COOH + 30 mL H20
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